In a group of N people (labelled 0, 1, 2, ..., N-1), each person has different amounts of money, and different levels of quietness. For convenience, we'll call the person with label x, simply "person x". We'll say that richer[i] = [x, y] if pers…
In a group of N people (labelled 0, 1, 2, ..., N-1), each person has different amounts of money, and different levels of quietness. For convenience, we'll call the person with label x, simply "person x". We'll say that richer[i] = [x, y] if pers…
[LeetCode]851. Loud and Rich 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/loud-and-rich/description/ 题目描述: In a group of N people (labelled 0, 1, 2, -, N-1), each person ha…
Inorder Successor in BST 要点:这题要注意的是如果不是BST,没法从树结构上从root向那边找p,只能遍历.而根据BST,可以只走正确方向 如果不检查right子树,可以从root到下,但invariant是root!=null.而检查右子树,invariant可以是root!=p 错误点: 不是找到某个>p.val,而是要找到最接近的p.val:所以loop终止条件是直到p==root or root is None,过程中只要>p.val就记录successor:这…
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All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) . Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…