Easy Finding Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15668   Accepted: 4163 Description Given a M×N matrix A. Aij ∈ {0, 1} (0 ≤ i < M, 0 ≤ j < N), could you find some rows that let every cloumn contains and only contains one 1.…

Easy Finding Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16178   Accepted: 4343 Description Given a M×N matrix A. Aij ∈ {0, 1} (0 ≤ i < M, 0 ≤ j < N), could you find some rows that let every cloumn contains and only contains one 1.…

题目链接:http://poj.org/problem?id=3740 题意: 是否从0,1矩阵中选出若干行,使得新的矩阵每一列有且仅有一个1? 原矩阵N*M $ 1<= N <= 16 $ , $ 1 <= M <= 300$ 解法1:由于行数不多,二进制枚举选出的行数,时间复杂度为O((1<<16)*K), 其中K即为判断选出的行数是否存在相同的列中有重复的1: 优化:将1状压即可,这样300的列值,压缩在int的32位中,使得列数“好像”小于10了:这样每次只需要…

Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16202   Accepted: 4349 Description Given a M×N matrix A. Aij ∈ {0, 1} (0 ≤ i < M, 0 ≤ j < N), could you find some rows that let every cloumn contains and only contains one 1. Input There a…

题目链接 dlx的第一题, 真是坎坷..... #include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <map> #include <set> #include <string> #include <que…

#include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; ; ; int A[R][C]; int n,m; int ff[R][R]; int flag; int U[R]; int cnt; int sum[C]; void DFS(int tot,int x,int now) { int ii,i,j; ; if(x==tot)…

传送门:http://poj.org/problem?id=3074 DLX 数独的9*9的模板题. 具体建模详见下面这篇论文.其中9*9的数独怎么转化到精确覆盖问题,以及相关矩阵行列的定义都在下文中,描述的十分清晰 http://wenku.baidu.com/view/4ab7bd00a6c30c2259019eae.html 有关Dancing Links的英文论文详见下面链接 http://wenku.baidu.com/view/60eb28ded15abe23482f4d77.htm…

显然这是一道dfs简单题 或许匹配也能做 然而用了dancing links 显然这也是一道模板题 好的吧 调了一上午 终于弄好了模板 Easy Finding Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19052   Accepted: 5273 Description Given a M×N matrix A. Aij ∈ {0, 1} (0 ≤ i < M, 0 ≤ j < N), could you fin…

[题目链接] http://poj.org/problem?id=3740 [算法] Dancing Links算法解精确覆盖问题 详见这篇文章 : https://www.cnblogs.com/grenet/p/3145800.html [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #incl…

Dancing Links学习:http://www.cnblogs.com/steady/archive/2011/03/15/1984791.html 以及图文学习:http://www.cnblogs.com/grenet/p/3145800.html 思路:这题是Dancing Links即DLX的最简单题目了吧,看懂了这个知识点之后.也不想自己敲了.然后搜索了好多个代码模板.认为这个我比較好理解也比較好掌握.然后就用这个模板了. #include<iostream> #include…