[LeetCode]Find Pivot】的更多相关文章

Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…
Find Pivot: Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the righ…
这是悦乐书的第304次更新,第323篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第172题(顺位题号是724).给定一个整数nums数组,编写一个返回此数组的"pivot"索引的方法.我们将pivot索引定义为索引,其中索引左边的数字之和等于索引右边的数字之和.如果不存在这样的索引,我们应该返回-1. 如果有多个数据透视索引,则应返回最左侧的数据透视索引.例如: 输入:nums = [1,7,3,6,5,6] 输出:3 说明:索引3左侧的数字之和(num…
leetcode 724. Find Pivot Index 题目描述:在数组中找到一个值,使得该值两边所有值的和相等.如果值存在,返回该值的索引,否则返回-1 思路:遍历两遍数组,第一遍求出数组的和,第二遍开始,保存左边所有的值的和,当左边值的和的2倍加上当前值等于数组和时,就是要找的索引.时间复杂度为o(n),空间复杂度为o(1). class Solution(object): def pivotIndex(self, nums): """ :type nums: Li…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 先求和,再遍历 日期 题目地址:https://leetcode.com/problems/find-pivot-index/description/ 题目描述 Given an array of integers nums, write a method that returns the "pivot" index of this arr…
Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…
Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3742 访问. 给定一个整数类型的数组 nums,请编写一个能够返回数组"中心索引"的方法. 我们是这样定义数组中心索引的:数组中心索引的左侧所有元素相加的和等于右侧所有元素相加的和. 如果数组不存在中心索引,那么我们应该返回 -1.如果数组有多个中心索引,那么我们应该返回最靠近左边的那一个. 输入: nums = [1, 7, 3, 6, 5, 6]…
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, 1 ≤ k ≤ array'…
Follow up for "Find Minimum in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might be…