Description 有一个集合U={1,2,…,n),要从中选择k个元素作为一个子集A.若a∈A,则要有a*X不属于A,x是一个给定的数.求可选方案对M取模后的值. 1< = N< = 10^18,2< = m< = 1000000,0< = K< = 1000,2< = x< = 10. Input 第一行输入N,M,K,X Output 如题 将不能共存的数连边,每个联通块都是一条链,计算出每个长度的链的条数,以及每个长度的链上取0~k个数的方案数,…

Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 分析: 因为有重…

Given a set of distinct integers, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] 分析:  用位操作非常简单,对于n个数来说共有2…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1…

求集合的所有子集问题 LeetCode:Subsets Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is:…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. 就是找出数字的全部子集. 我的思路: 设输入是 1  2  3  4 先把输入从小到大排序 长度 0 : [] 长度 1 : 把输入数据从第一…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

Subsets Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,3], a solution is: [ [3], [1], [2], [1…

子集系列问题: Coding 问题中有时会出现这样的问题:给定一个集合,求出这个集合所有的子集(所谓子集,就是包含原集合中的一部分元素的集合). 或者求出满足一定要求的子集,比如子集中元素总和为定值,子集元素个数为定值等等. 我把它们归类为子集系列问题. leetcode上原题链接: 思路分析: 思路一 可以用递推的思想,观察S=[], S =[1], S = [1, 2] 时解的变化. 可以发现S=[1, 2] 的解就是 把S = [1]的所有解末尾添上2,然后再并上S = [1]里面的原有解…

9.4 Write a method to return all subsets of a set. LeetCode上的原题,请参见我之前的博客Subsets 子集合和Subsets II 子集合之二. 解法一: class Solution { public: vector<vector<int> > getSubsets(vector<int> &S) { vector<vector<); ; i < S.size(); ++i) { i…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

Subsets Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,…

Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If nums = [1,2,3], a solution is: [ [3], [1], [2], [1,2…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], […

题目来源 https://leetcode.com/problems/subsets-ii/ Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate su…

题目来源 https://leetcode.com/problems/subsets/ Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. 题意分析 Input: :type nums:…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1…

题意: 给一个集合,有n个可能相同的元素,求出所有的子集(包括空集,但是不能重复). 思路: 看这个就差不多了.LEETCODE SUBSETS (DFS) class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { sort(nums.begin(),nums.end()); DFS(,nums,tmp); ans.push_back(vector<int>()…

题意: 给一个集合,有n个互不相同的元素,求出所有的子集(包括空集,但是不能重复). 思路: DFS方法:由于集合中的元素是不可能出现相同的,所以不用解决相同的元素而导致重复统计. class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { sort(nums.begin(),nums.end()); DFS(,nums,tmp); return ans; } void DF…

题目: Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a sol…

题目: Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1], [2], […

原题地址 跟Subsets(参见这篇文章)类似. 但因为有重复元素,所以要考虑去重问题. 什么情况下会出现重复呢?比如S = {5, 5, 5},如果要选1个5,一共有C(3,1)=3种选法,即100, 010, 001,这三种情况在集合的角度看是重复的情况.如果要选2个5,共有C(3,2)=3种选法,即011, 101, 110,这三种情况在集合的角度上看也是重复的. 本质在于,如果要在重复出现的数字当中选择若干个,则只能保留一种取法,其他的都是重复.即,这些重复数字对应的二进制位当中,只能保…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], […

原题地址 有两种方法: 1. 对于序列S,其子集可以对应为一个二进制数,每一位对应集合中的某个数字,0代表不选,1代表选,比如S={1,2,3},则子集合就是3bit的所有二进制数. 所以,照着二进制位去构造解空间即可. 2. 也可以用DFS做,对于每个元素,要么选,要么不选. 记得先排序,因为结果集的数字要从小到大出现. 代码(DFS版本): vector<vector<int> > res; void dfs(vector<int> &S, vector&l…

题目 带重复元素的子集 给定一个可能具有重复数字的列表,返回其所有可能的子集 样例 如果 S = [1,2,2],一个可能的答案为: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 注意 子集中的每个元素都是非降序的 两个子集间的顺序是无关紧要的 解集中不能包含重复子集 挑战 你可以同时用递归与非递归的方式解决么? 解题 一个很简单的想法就是在上一题目中增加判断是否已经存在某个子集 class Solution: """ @param S: A…

题目 子集 给定一个含不同整数的集合,返回其所有的子集 样例 如果 S = [1,2,3],有如下的解: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] 注意 子集中的元素排列必须是非降序的,解集必须不包含重复的子集 挑战 你可以同时用递归与非递归的方式解决么? 解题 根据上面求排列的思想很类似,还是深度优先遍历.由于输出每个子集需要升序,所以要先对数组进行排序.求出所以的子集,也就是求出所以的组合方式 + 空集 问题转化为求组合方式的问题…

题目: Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a sol…