Handshakes Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3932 Description Last week, n students participated in the annual programming contest of Marjar University. Students are labeled from 1 t…

D. Handshakes Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/534/problem/D Description On February, 30th n students came in the Center for Training Olympiad Programmers (CTOP) of the Berland State University. They came one…

传送门 D. Handshakes time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output On February, 30th n students came in the Center for Training Olympiad Programmers (CTOP) of the Berland State University. T…

题目链接:https://leetcode-cn.com/problems/handshakes-that-dont-cross/ You are given an even number of people num_people that stand around a circle and each person shakes hands with someone else, so that there are num_people / 2 handshakes total. Return t…

水题. 算一下每个人和之前的人握手次数+之后的人和这个人握手次数.取最大值. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; +; int n; int a[maxn],dp[maxn]; int main() { int T; scanf("%d",&T); while(T--) { scanf…

Description Last week, n students participated in the annual programming contest of Marjar University. Students are labeled from 1 to n. They came to the competition area one by one, one after another in the increasing order of their label. Each of t…

#include <stdio.h> #include <algorithm> #include <set> using namespace std; #define forn(i, n) for (int i = 0; i < int(n); i++) typedef pair<int, int> pii; ; int n; ]; int ans[N]; int main() { scanf("%d", &n); forn…

Last week, n students participated in the annual programming contest of Marjar University. Students are labeled from 1 to n. They came to the competition area one by one, one after another in the increasing order of their label. Each of them went in,…

题目链接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3932 题意 给出 N 个人,然后 1-N 然后 从 1 - N 一个一个的进,每个人 进去 都可以在在座的人握手,然后给出那个人握手的次数 要求出 握手次数的最大值 思路 只要进来的人握手次数>=1 那么 本来已经在区域内的人 那个当前这个人的握手次数 就是其给出的握手次数,本来已经在区域内的人握手次数都+1,因为都是有可能的 然后实际发现 ,可以FOR 一遍…

[题目链接]:http://codeforces.com/contest/534/problem/D [题意] n个人依次进入一个房间; 进进来的人会和房间里面没有组队的人握一次手; (这里的握手只计算主动握手的那个人的握手次数); (任意时刻,任意3个人都能组队): 给出每个人的握手信息; 问你n个人进入房间的顺序是怎么样的. [题解] 一开始房间里面一个人都没有; 这个时候,看看哪个人握手的次数为0; -> 房间里面变成了两个人,然后看看哪个人的握手次数为2 -> 房间里面变成了三个人,然…

题目如下: 解题思路:动态规划.记dp[i] = v表示由i个人组成的圈子一共有v种握手的方法.对于一个由n个人组成的圈子,编号为0的人一共可以和编号为 (1,3,5....,n-1)的握手,这也很好理解,假设编号为0的人和编号为2的人握手,那么编号为1的人就被包在两人的连线的一侧,而同侧没有其他人可以握手.假设编号为0的人和编号为i的人握手,可以理解成0~i之间的连线把其余人分成了两部分,一部分的人编号是1~i-1,另外一部分的编号是i+1~n-1,这两部分分别形成独立的圈子,所以编号为0的人…

官方资料:Chrome Developer Tools: Network Panel 一.chrome Developer Tools:Network Panel 从网络面板中可以获取很多有用信息,如详细的时间数据,http请求头响应头,cookies,WebSocket数据. 通过分析这些数据,可以知道哪个资源加载耗时最久,谁发起的网络请求,这些对性能优化很有帮助. 这些数据的获取都是通过一个api来完成的,Resource Timing API. 我们不需要知道它的实现原理,只要知道它能提供…

Kali2.0系统自带的WiFite脚本代码中有几行错误,以下是修正后的代码: #!/usr/bin/python # -*- coding: utf-8 -*- """ wifite author: derv82 at gmail author: bwall @botnet_hunter (ballastsec@gmail.com) author: drone @dronesec (ballastsec@gmail.com) Thanks to everyone that…

A first thought system architecture (pulling mode) is one that the server doesn't keep client information and the client takes a more active part in retrieving updates from the server, Note the previous model manager which is responsible for both the…

Wifite v2 is now available What's new in this version: support for cracking WPS-encrypted networks (via reaver) 2 new WEP attacks more accurate WPA handshake capture various bug fixes Version 2 does not include a GUI, so everything must be done at th…

html,body { } .CodeMirror { height: auto } .CodeMirror-scroll { } .CodeMirror-lines { padding: 4px 0px } .CodeMirror pre { } .CodeMirror-scrollbar-filler,.CodeMirror-gutter-filler { background-color: white } .CodeMirror-gutters { border-right-width:…

(一)SSL/TLS协议运行机制的概述 一.作用 不使用SSL/TLS的HTTP通信,就是不加密的通信.所有信息明文传播,带来了三大风险. (1) 窃听风险(eavesdropping):第三方可以获知通信内容. (2) 篡改风险(tampering):第三方可以修改通信内容. (3) 冒充风险(pretending):第三方可以冒充他人身份参与通信. SSL/TLS协议是为了解决这三大风险而设计的,希望达到: (1) 所有信息都是加密传播,第三方无法窃听. (2) 具有校验机制,一旦被篡改,通…

A. Exam 果然,并没有3分钟秒掉水题的能力,=_=|| n <= 4的时候特判.n >= 5的时候将奇数和偶数分开输出即可保证相邻的两数不处在相邻的位置. #include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; ) puts("1\n1"); ) puts("2\n1 3\n"); ) puts("4\n2 4 1 3\…

Sending is time spent uploading the data/request to the server. It occurs between blocking and waiting. For example, if I post back an ASPX page this would indicate the amount of time it took to upload the request (including the values of the forms a…

Bayeux 协议-- Bayeux 1.0草案1 本备忘录状态 This document specifies a protocol for the Internet community, and requests discussion and suggestions for improvement. This memo is written in the style and spirit of an IETF RFC but is not, as of yet, an official IE…

The QSslSocket class provides an SSL encrypted socket for both clients and servers. More... Header: #include <QSslSocket> Since: Qt 4.3 Inherits: QTcpSocket Note: All functions in this class are reentrant. List of all members, including inherited me…

How HTML5 Web Sockets Interact With Proxy Servers Posted by Peter Lubberson Mar 16, 2010 With the recent explosion of WebSocket server implementations, a lot of questions have come up about how HTML5 Web Sockets deal with proxy servers, firewalls, an…

https://msdn.microsoft.com/en-us/library/ff647787.aspx Retired Content This content is outdated and is no longer being maintained. It is provided as a courtesy for individuals who are still using these technologies. This page may contain URLs that we…

Chrome Developer Tools:Network Panel说明   官方资料:Chrome Developer Tools: Network Panel 一.chrome Developer Tools:Network Panel 从网络面板中可以获取很多有用信息,如详细的时间数据,http请求头响应头,cookies,WebSocket数据. 通过分析这些数据,可以知道哪个资源加载耗时最久,谁发起的网络请求,这些对性能优化很有帮助. 这些数据的获取都是通过一个api来完成的,Re…

又水了一发Codeforce ,这次继续发发题解顺便给自己PKUSC攒攒人品吧 CodeForces 438C:The Child and Polygon: 描述:给出一个多边形,求三角剖分的方案数(n<=200). 首先很明显可能是区间dp,我们可以记f[i][j]为从i到j的这个多边形的三角剖分数,那么f[i][j]=f[i][k]*f[j][k]*(i,j,k是否为1个合格的三角形) Code: #include<cstdio> #include<iostream> #…

Chrome的开发者工具(Chrome Developer Tools) 按F12 https://developer.chrome.com/devtools/index http://www.w3school.com.cn/html/html_intro.asp http://www.cnblogs.com/QLeelulu/archive/2011/08/28/2156402.html http://wenku.baidu.com/link?url=fz5kfYH9wlEkqHpkPiP7b…

3 月 20 日,Oracle 宣布 Java 10 正式发布. 官方已提供下载:http://www.oracle.com/technetwork/java/javase/downloads/index.html . 在 Java 9 之后,Java 采用了基于时间发布的策略,每 6 个月一个版本.这是采用新的发布策略之后的第一个版本. Java 10 主要有 12 个新特性. 具体来看看. JEP 286: Local-Variable Type Inference 局部变量的类型推导. 很…

前面一篇我们说了什么? 这是这个关于NSURLSession的第二篇文章,第一篇再加上这篇文章,就大概的把NSURLSession的API以及一些简单使用我们也就说的差不多了,这篇文章总结哪些点呢?相信看顾哦第一篇文章的小伙伴都知道,在开始写这篇文章之前我们说说上一篇文章我们写了些什么. 1.NSURLRequest 2.NSURLSession 3.NSURLSessionTask 以及它的三个子类:NSURLSessionDataTask/NSURLSessionDownloadTask/N…

基础架构 拓扑图 Switching Path L3 routing at aggregation layer L2 switching at access layer L3 switch融合了三种功能: RP, router processor, 处理路由协议 SP, switch processor, 处理L2协议 ASIC, Application-specific integrated circuit专用集成电路,用于重写header的 对于traffic forwarding有几种方法…

小结: 1. 小文件存储于一个文件中: 在内部,磁盘缓存(disk cache)实现了它自己的一组数据结构, 它们被存储在一个单独的缓存目录里.其中有索引文件(在浏览器启动时加载到内存中),数据文件(存储着实际数据,以及HTTP头以及其它信息).比较有趣 的是,16KB以下的文件存储于共同的数据块文件中(data block-files,即小文件集中存储于一个大文件中),其它较大的文件才会存储到自己专属的文件中.最后,磁盘缓存的淘汰策略是维护一个LRU,通 过比如访问频率和资源的使用时间(age…