492. Construct the Rectangle】的更多相关文章

problem 492. Construct the Rectangle 参考 1. Leetcode_492. Construct the Rectangle; 完…
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements: 1…
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements: 1…
题目: or a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 python解法 日期 题目地址:https://leetcode.com/problems/construct-the-rectangle/#/description 题目描述 For a web developer, it is very important to know how to design a web page's si…
static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: vector<int> constructRectangle(int area) { vector<int> res; int test=sqrt(area); ;test--) { ) return {area/test,test}; } } }; 从开方出来的数一个个找…
详见:https://leetcode.com/problems/construct-the-rectangle/description/ C++: class Solution { public: vector<int> constructRectangle(int area) { int l=sqrt(area),w=sqrt(area); while(l*w!=area) { if(l*w<area) { ++l; } else { --w; } } return {l,w}; }…
LeetCode--Construct the Rectangle Question For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page's area, your job by now is to design a rectangular web page, whose length L and wi…
1209. Construct the Rectangle class Solution { public: /** * @param area: web page’s area * @return: the length L and the width W of the web page you designed in sequence */ vector<int> constructRectangle(int area) { // Write your code here int st…
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements: 1…
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements: 1…
这是悦乐书的第243次更新,第256篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第110题(顺位题号是492).对于Web开发人员,了解如何设计网页的大小非常重要.因此,给定一个特定的矩形网页区域,您现在的工作是设计一个矩形网页,其长度L和宽度W满足以下要求: 1.您设计的矩形网页区域必须等于给定的目标区域. 2.宽度W不应大于长度L,这意味着L> = W. 3.长度L和宽度W之间的差异应尽可能小. 您需要按顺序输出您设计的网页的长度L和宽度W. 例: 输入:4…
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements: 1…
原题链接在这里:https://leetcode.com/problems/construct-the-rectangle/ 题目: For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web pag…
作为一位web开发者, 懂得怎样去规划一个页面的尺寸是很重要的. 现给定一个具体的矩形页面面积,你的任务是设计一个长度为 L 和宽度为 W 且满足以下要求的矩形的页面.要求: 1. 你设计的矩形页面必须等于给定的目标面积. 2. 宽度 W 不应大于长度 L,换言之,要求 L >= W . 3. 长度 L 和宽度 W 之间的差距应当尽可能小. 你需要按顺序输出你设计的页面的长度 L 和宽度 W. 示例: 输入: 4 输出: [2, 2] 解释: 目标面积是 4, 所有可能的构造方案有 [1,4],…
突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…
是周六晚上的几道题,晚上11点半,睡的早,起不来! 494. Target Sum 分析:看完这题,看到数据范围,长度20,枚举就是1<<20 = 1e6, 然后单次20,总共就是2e8,感觉应该是暴力枚举,然后我就按照二进制的方式写了代码,tle了,我感觉应该可以过啊,然后就用dfs写了一下,刚好能过,卡的时间,感觉应该有优化的地方.其实正确的思路是dp,我刚开始感觉也是dp,因为要计算所有的可能,感觉dp也是暴力,算所有可能出现的情况,感觉跟暴力差不多!今天看了下别人的分析,是自己分析错了…
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…
源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…
终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…
492. Construct the Rectangle Input: 4 Output: [2, 2] Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not opti…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…
1.Instance Constructors and Classes (Reference Types) Constructors methods : 1.allow an instance of a type to be initialized to a good state. 2.are always called .ctor (for constructor) in a method definition metadata table. 3.When creating an instan…
转载请注明原文地址:http://www.cnblogs.com/ygj0930/p/6415011.html 16:Invert Binary Tree 此题:以根为对称轴,反转二叉树. 思路:看到二叉树,我们第一时间要想到处理二叉树的常用方法——BFS.DFS,更常用的是DFS.此题我们先用BFS来思考:BFS是逐层每个结点处理,即通过交换每层结点的位置来达到整体交换.我们可以用队列+栈来实现,用队列处理实现按层遍历,用栈实现当前层结点位置倒转,然后从根结点开始,逐层重新建树.无疑,这很麻烦…
题目链接: F. Couple Cover time limit per test 3 seconds memory limit per test 512 megabytes input standard input output standard output Couple Cover, a wildly popular luck-based game, is about to begin! Two players must work together to construct a recta…
Couple Cover, a wildly popular luck-based game, is about to begin! Two players must work together to construct a rectangle. A bag with nballs, each with an integer written on it, is placed on the table. The first player reaches in and grabs a ball ra…
引言 我有一个显示屏模块: 模块上有一个128*64的单色显示屏,一个单片机(B)控制它显示的内容.单片机的I²C总线通过四边上的排针排母连接到其他单片机(A)上,A给B发送指令,B绘图. B可以向屏幕逐字节发送显示数据,但是不能读取,所以程序中必须设置显存.一帧需要1024字节,但是单片机B只有512字节内存,其中只有256字节可以分配为显存.解决这个问题的方法是在B的程序中把显示屏分成4个区域,保存所有要绘制的图形的信息,每次在256字节中绘制1/4屏,分批绘制.发送. 简而言之,我需要维护…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…
from manim import * #导入manim命名空间 #这是一个最基本的manim结构,类名叫做BaseFrame,传入一个场景Scene,并且包含一个construct方法,传入self class BaseFrame(Scene): def construct(self): self.wait() class CreateCircle(Scene): def construct(self): circle = Circle() # 创建了一个Circle对象:circle cir…