Leetcode354 暴力的方法是显而易见的 O(n^2)构造一个DAG找最长链即可. 也有办法优化到O(nlogn) 注意 信封的方向是不能转换的. 对第一维从小到大排序,第一维相同第二维从大到小排序. 维护一个符合题意的队列,当队列中的第二维均比当前信封的第二维小时,必然可以增加到队尾. 如果不然,可以让当前信封作为“替补”,它可以在恰当的时候代替恰好比它大的信封. 当替补们足够替换所有已有信封时,就可以增加新的信封了. 比较抽象,不过这个技巧很有趣. 看代码吧,很清晰. class So…

https://leetcode.com/problems/russian-doll-envelopes/ You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater tha…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

题目描述: You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. Wh…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope.What is t…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

201521123061 <Java程序设计>第十二周学习总结 1. 本周学习总结 1.1 以你喜欢的方式(思维导图或其他)归纳总结多流与文件相关内容. 2. 书面作业 将Student对象(属性:int id, String name,int age,double grade)写入文件student.data.从文件读出显示. 1. 字符流与文本文件:使用 PrintWriter(写),BufferedReader(读) 1.1 生成的三个学生对象,使用PrintWriter的println…

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201521123038 <Java程序设计> 第十二周学习总结 1. 本周学习总结 1.1 以你喜欢的方式(思维导图或其他)归纳总结多流与文件相关内容. 2. 书面作业 将Student对象(属性:int id, String name,int age,double grade)写入文件student.data.从文件读出显示. 1. 字符流与文本文件:使用 PrintWriter(写),BufferedReader(读) 1.1 生成的三个学生对象,使用PrintWriter的printl…