题目描述 Farmer John's N (1 <= N <= 100,000) cows are lined up in a row andnumbered 1..N. The cows are conducting another one of their strangeprotests, so each cow i is holding up a sign with an integer A_i(-10,000 <= A_i <= 10,000). FJ knows the…
3790: 神奇项链 Description 母亲节就要到了,小 H 准备送给她一个特殊的项链.这个项链可以看作一个用小写字 母组成的字符串,每个小写字母表示一种颜色.为了制作这个项链,小 H 购买了两个机器.第一个机器可以生成所有形式的回文串,第二个机器可以把两个回文串连接起来,而且第二个机器还有一个特殊的性质:假如一个字符串的后缀和一个字符串的前缀是完全相同的,那么可以将这个重复部分重叠.例如:aba和aca连接起来,可以生成串abaaca或 abaca.现在给出目标项链的样式,询问你需要使…
最长上升子序列.虽然数据可以直接n方但是另写了个nlogn的 转移:f[i]=max(f[j]+1)(a[j]<a[i]) O(n^2) #include<iostream> #include<cstdio> using namespace std; const int N=5005; int n,a[N],f[N],ans; int read() { int r=0,f=1; char p=getchar(); while(p>'9'||p<'0') { if(…
把长度转成右端点,按右端点排升序,f[i]=max(f[j]&&r[j]<l[i]),因为r是有序的,所以可以直接二分出能转移的区间(1,w),然后用树状数组维护区间f的max,每次转移的时候直接从树状数组上查询前缀max即可,然后把更新出来的f[i]update进树状数组 #include<iostream> #include<cstdio> #include<algorithm> using namespace std; const int N…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2227 Find the nondecreasing subsequences Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) …
题目链接: C. Subsequences time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is…
树状数组维护DP + 高精度 Description These days, Sempr is crazed on one problem named Crazy Thair. Given N (1 ≤ N ≤ 50000) numbers, which are no more than 109, Crazy Thair is a group of 5 numbers {i, j, k, l, m} satisfying: 1 ≤ i < j < k < l < m ≤ N Ai…