转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…

http://www.cnblogs.com/TenosDoIt/p/3735309.html https://blog.csdn.net/fly_yr/article/details/48055617 class Solution { public: string multiply(string num1, string num2) { int len1 = num1.length(); int len2 = num2.length(); vector<); ; 第一轮乘出来的结果只有len1…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

1. 原始题目 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456" 输出: "56088" 说明: num1 和 num2 的长度小于110. num1 和…

给定两个以字符串表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积.注意:    num1 和 num2 的长度均小于110.    num1 和 num2 均只包含数字 0-9.    num1 和 num2 均不以零开头.    你不能使用任何内置的大整数库或直接将输入转换为整数.详见:https://leetcode.com/problems/multiply-strings/description/ Java实现: class Solution { public…

给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456" 输出: "56088" 说明: num1 和 num2 的长度小于110. num1 和 num2 只包…

网址:https://leetcode.com/problems/multiply-strings/submissions/ 参考:https://leetcode.com/problems/multiply-strings/discuss/17605/Easiest-JAVA-Solution-with-Graph-Explanation 把乘法分解为最最基础的加法,从后往前循环. class Solution { public: string multiply(string num1, st…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:计算字符串对应数字的乘积.参考JustDoIT的博客. 思路:先用一维向量存放计算的中间值,中间值存放对应位置乘积的和(暂不考虑进位的情况):然后针对进位的情况,进行计算:注意要跳…

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…