id=2965">The Pilots Brothers' refrigerator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18080   Accepted: 6855   Special Judge Description The game "The Pilots Brothers: following the stripy elephant" has a quest where a…

The Pilots Brothers' refrigerator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19356   Accepted: 7412   Special Judge Description The game "The Pilots Brothers: following the stripy elephant" has a quest where a player needs to o…

The Pilots Brothers' refrigerator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18040   Accepted: 6841   Special Judge Description The game "The Pilots Brothers: following the stripy elephant" has a quest where a player needs to o…

链接:poj 2965 题意:给定一个4*4矩阵状态,代表门的16个把手.'+'代表关,'-'代表开.当16个把手都为开(即'-')时.门才干打开,问至少要几步门才干打开 改变状态规则:选定16个把手中的随意一个,能够改变其本身以及同行同列的状态(即若为开,则变为关,若为关,则变为开),这一次操作为一步. 分析:这题与poj 1753思路差点儿相同,每一个把手最多改变一次状态, 全部整个矩阵最多改变16次状态 思路:直接dfs枚举全部状态,直到找到目标状态 可是要打印路径,全部应在dfs时记录路…

转载请注明出处:http://blog.csdn.net/u012860063? viewmode=contents 题目链接:http://poj.org/problem? id=2965 ----------------------------------------------------------------------------------------------------------------------------------------------------------…

[题目链接] http://poj.org/problem?id=2965 [算法] 位运算 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #includ…

题目链接:http://poj.org/problem?id=2965 The Pilots Brothers' refrigerator Time Limit: 1000MS Memory Limit: 65536K Description The game "The Pilots Brothers: following the stripy elephant" has a quest where a player needs to open a refrigerator. Ther…

I - The Pilots Brothers' refrigerator Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description The game "The Pilots Brothers: following the stripy elephant" has a quest where a player needs to op…

The Pilots Brothers' refrigerator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 22286   Accepted: 8603   Special Judge Description The game “The Pilots Brothers: following the stripy elephant” has a quest where a player needs to open a…

题目地址:http://poj.org/problem?id=2965 /* 题意:4*4的矩形,改变任意点,把所有'+'变成'-',,每一次同行同列的都会反转,求最小步数,并打印方案 DFS:把'+'记为1, '-'记为0 1. 从(1, 1)走到(4, 4),每一点DFS两次(改点反转或不反转):used记录反转的位置 详细解释:http://poj.org/showmessage?message_id=346723 2. 比较巧妙的解法:抓住'+'位置反转,'-'位置相对不反转的特点,从状…