题目链接: https://cn.vjudge.net/problem/POJ-3037 Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the top left corner of an R (1 <= R <= 100) by C (1 <= C <= 100) grid of elevati…

Skiing Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4668   Accepted: 1242   Special Judge Description Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the top left c…

Skiing Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the top left corner of an R (1 <= R <= 100) by C (1 <= C <= 100) grid of elevations E (-25 <= E <= 25). In order…

Skiing Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4810   Accepted: 1287   Special Judge Description Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the top left c…

Skiing POJ 3037 很奇怪的最短路问题 题意 题意:你在一个R*C网格的左上角,现在问你从左上角走到右下角需要的最少时间.其中网格中的任意两点的时间花费可以计算出来. 解题思路 这个需要发现一个规律,就是从左上角到其他任意一点,无论选择哪条路径,到达该点的速度都是固定的. 例如对于下面的一个矩阵: 1 5 3 6 3 5 2 4 3 可以发现我们想要计算数值为2的点的速度的话,\[v_2=v_1*2^{1-2}*\],路径是这样的\[1->6->2\], 然后\[v_2=v_1*2…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5769    Accepted Submission(s): 2316 Problem Description Although winter is far away, squirrels have to work day and night to save b…

题意: 思路: 我们可以发现 到每个点的速度是一样的 那这就成水题了-. 裸的SPFA跑一哈 搞定 //By SiriusRen #include <cmath> #include <queue> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int v,n,m,map[105][105],xx[]={1,-1,0,0},yy[]={0…

poj——3037 Skiing Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4921   Accepted: 1315   Special Judge Description Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the…

先简单介绍一下最短路径: 最短路径是啥?就是一个带边值的图中从某一个顶点到另外一个顶点的最短路径. 官方定义:对于内网图而言,最短路径是指两顶点之间经过的边上权值之和最小的路径. 并且我们称路径上的第一个顶点为源点,最后一个顶点为终点. 由于非内网图没有边上的权值,所谓的最短路径其实是指两顶点之间经过的边数最少的路径. 我们时常会面临着对路径选择的决策问题,例如在中国的一些一线城市如北京.上海.广州.深圳等,一般从A点到到达B点都要通过几次地铁.公交的换乘才可以到达. 有些朋友想用最短对的时间,…

转自——http://blog.csdn.net/qwe20060514/article/details/8112550 =============================以下是最小生成树+并查集======================================[HDU]1213   How Many Tables   基础并查集★1272   小希的迷宫   基础并查集★1325&&poj1308  Is It A Tree?   基础并查集★1856   More i…