F. The Sum of the k-th Powers 题目连接: http://www.codeforces.com/contest/622/problem/F Description There are well-known formulas: , , . Also mathematicians found similar formulas for higher degrees. Find the value of the sum modulo 109 + 7 (so you shoul…

题目链接 求sigma(i : 1 to n)i^k. 为了做这个题这两天真是补了不少数论, 之前连乘法逆元都不知道... 关于拉格朗日插值法, 我是看的这里http://www.guokr.com/post/456777/, 还挺有趣... 根据题目给出的例子我们可以发现, k次方的通项公式的最高次是k+1次, 根据拉格朗日插值法, 构建一个k+1次的方程需要k+2项. 然后公式是  , 对于这个题, p[i]就是i^k+(i-1)^k+(i-2)^k+.....+1^k, 这部分可以预处理出…

用的dls的板子,因为看不懂调了好久...果然用别人的板子就是这么蛋疼- -|| num数组0~k+1储存了k+2个值,且这k+2个值是自然数i的k次方而不是次方和,dls的板子自己帮你算和的...搞得我弄了好久 #include <iostream> #include <string.h> #include <cstdio> #include <vector> #include <queue> #include <assert.h>…

CF622F The Sum of the k-th Powers 题意:给\(n\)和\(k\),让你求\(\sum\limits_{i = 1} ^ n i^k \ mod \ 10^9 + 7\).\((1 \le n \le 10^9,0 \le k \le 10^6)\) 好,我们先不看题,来补一些数学. 考虑这样一个序列 \[ h_0,h_1,\dots,h_n,\dots \] 我们定义它的一个差分序列(一阶) \[ \Delta h_0, \Delta h_1, \dots ,…

题面 TJOI2018出CF原题弱化版是不是有点太过分了?对,就是 TJOI2018 教科书般的亵渎 然而我这个问题只会那个题的范围的m^3做法 回忆一下1到n求和是二次的,平方求和公式是三次的,立方求和公式是四次的,那m次方求和公式一定是个m+1次多项式 直接扔m+2个值进去把它插出来,因为是连续的可以做到线性(不算逆元) #include<cstdio> ,mod=1e9+; int n,k,ans,sum,fac[N],pre[N],suf[N]; int Qpow(int x,int…

The Sum of the k-th Powers There are well-known formulas: , , . Also mathematicians found similar formulas for higher degrees. Find the value of the sum modulo 109 + 7 (so you should find the remainder after dividing the answer by the value 109 + 7).…

Return the length of the shortest, non-empty, contiguous subarray of A with sum at least K. If there is no non-empty subarray with sum at least K, return -1. Example 1: Input: A = [1], K = 1 Output: 1 Example 2: Input: A = [1,2], K = 4 Output: -1 Exa…

Return the length of the shortest, non-empty, contiguous subarray of A with sum at least K. If there is no non-empty subarray with sum at least K, return -1. Example 1: Input: A = [1], K = 1 Output: 1 Example 2: Input: A = [1,2], K = 4 Output: -1 Exa…

https://leetcode.com/problems/shortest-subarray-with-sum-at-least-k/ 首先回顾一下求max子数组的值的方法是:记录一个前缀min值,然后扫一遍sum数组. 1.首先这里不需要最大,因为刚好够k就好了 2.这里需要距离最短.就是数组的长度最短. 这里的思路也一样,不过保存很多个min值,就是用一个队列,保存前缀的min值,不需要最min,只不过有更小的就更好. 也就是如果sum数组的值是: ..... 60, 40.....Y..…

Return the length of the shortest, non-empty, contiguous subarray of A with sum at least K. If there is no non-empty subarray with sum at least K, return -1. Example 1: Input: A = [1], K = 1 Output: 1 Example 2: Input: A = [1,2], K = 4 Output: -1 Exa…