旋转一个数组. function rotate(array,n){ var l =array.length,a=array.map(function(x){return x}),arr=[]; n=n-Math.floor(n/l)*l; for(var i=0;i<l;i++){ if((i+n)<l&&(i+n)>=0){ arr[i+n]=a[i]; } else if((i+n)>=l){ arr[i+n-l]=a[i]; } else if((i+n)&l…

1.关于leetcode 这是第一篇关于leetcode的题解,就先扯点关于leetcode的话. 其实很早前就在博客园看到过leetcode一些题解,总以为跟一般OJ大同小异,直到最近点开了一篇博文Leetcode 编程训练,无意间点进leetcode的主页看了下,乖乖,居然能用JavaScript提交代码(还能用python.ruby等)!瞬间来了兴趣,一口气把几十道水题都切完了,代码放在了github,有兴趣的可以参考或者帮忙review一下.对于个人认为有意思的题目,楼主也会时不时地写些…

Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro…

#189.    Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different…

Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to…

Title: Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". https://leetcode.com/problems/reverse-words-in-a-string/ 思路:先将字符串全部逆转,在将每个单词逆转.具体实现,要注意空格,所以对字符串倒过来处理. cla…

STL中的list就是一双向链表,可高效地进行插入删除元素. List 是 C++标准程式库 中的一个 类 ,可以简单视之为双向 连结串行 ,以线性列的方式管理物件集合.list 的特色是在集合的任何位置增加或删除元素都很快,但是不支持随机存取.list 是 C++标准程式库 提供的众多容器(container)之一,除此之外还有 vector .set.map.…等等.list 以模板方式实现(即泛型),可以处理任意型别的变量,包括使用者自定义的资料型态,例如:它可以是一个放置整数(int)型…

Rotate Array 本题目收获: 题目: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 思路: 我的思路:新建一个数组存放旋转后的内容,但是怎么把原数组的内容存放在数组中,不清楚. leetcode/discuss思路: 思路一:新建数组,复制原…

189. Rotate Array[easy] Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 differen…

题意:给定一个数组,将该数组的后k位移动到前n-k位之前.(本题在编程珠玑中第二章有讲) 思路: 方法一:将后K位用vector容器装起来,再移动前n-k位到后面,再将容器内k位插到前面. class Solution { public: void rotate(int nums[], int n, int k) { || k==n ) return; k %= n; vector<int> cha; cha.reserve(k); int i; for(i=n-k; i<n; i++)…