滑动窗口-Substring Search Problem

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滑动窗口-Substring Search Problem

2018-07-18 11:19:19 一.Minimum Window Substring 问题描述: 问题求解: public String minWindow(String s, String t) { String res = ""; if (t.length() > s.length()) return res; Map<Character, Integer> map = new HashMap<>(); for (int i = 0; i &l…

滑动窗口解决Substring Search Problem

2018-07-18 11:19:19 一.Minimum Window Substring 问题描述: 问题求解: public String minWindow(String s, String t) { String res = ""; if (t.length() > s.length()) return res; Map<Character, Integer> map = new HashMap<>(); for (int i = 0; i &l…

[Leetcode 3] 最长不重复子串 Longest substring without repeating 滑动窗口

[题目] Given a string, find the length of the longest substring without repeating characters. [举例] Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output:…

POJ 3320 Jessica's Reading Problem (滑动窗口)

题意:给定一个序列,求一个最短区间,使得这个区间包含所有的种类数. 析:最近刚做了几个滑动窗口的题,这个很明显也是,肯定不能暴力啊,时间承受不了啊,所以我们使用滑动窗口来解决,要算出所有的种数,我用set来计算的,当然也可以用别的, 由于要记录种类数,所以使用map来记录,删除和查找方便,说到这,这不就是水题了么. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <…

leetcode 3 Longest Substring Without Repeating Characters(滑动窗口)

用滑动窗口的思想来做.用一个unordered_map来查询之前的char有没有在现在的窗口中. class Solution { public: int lengthOfLongestSubstring(string s) { unordered_map<char,int>mp; ,now=;//now is the window's instant length ,e=;//the window's begin and end int len=s.length(); ;i<len;i…

[LeetCode] Sliding Window Maximum 滑动窗口最大值

Given an array nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position. For example,Given nums…