TIANKENG’s rice shop】的更多相关文章

TIANKENG's rice shop 题目链接: http://acm.hust.edu.cn/vjudge/contest/123316#problem/J Description TIANKENG managers a pan fried rice shop. There are n kinds of fried rice numbered 1-n. TIANKENG will spend t time for once frying. Because the pan is so sma…
HDU 4884 TIANKENG's rice shop 题目链接 题意:模拟题.转一篇题意 思路:就模拟就可以.注意每次炒完之后就能够接单 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int N = 1005; int T, n, t, k, m; struct Person { int t, p, num, ans; } p[N];…
Problem Description TIANKENG managers a pan fried rice shop. There are n kinds of fried rice numbered 1-n. TIANKENG will spend t time for once frying. Because the pan is so small, TIANKENG can fry k bowls of fried rice with same kind at most. Assumin…
简单模拟,注意并不是完全按照FIFO的顺序.比如第i个人的id为k,那么就算第i+1人的id不为k,也会检查他后续的排队人是否有id为k的. #include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 1005 typedef struct { int tt; int id; int num; int ans; } need_st; need_st needs[MAXN]; int main(…
# include <cstdio> # include <algorithm> # include <cstring> # include <cstdlib> using namespace std; int max(int a,int b) { return a>b?a:b; } int main() { int T,n,t,k,m,i,hh,min,id,num,x; int last[1010];//最后一次開始炒饭的时间 int cot[10…
TIANKENG’s rice shop Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 212    Accepted Submission(s): 9 Problem Description TIANKENG managers a pan fried rice shop. There are n kinds of fried rice…
E. Thief in a Shop time limit per test 5 seconds memory limit per test 512 megabytes input standard input output standard output A thief made his way to a shop. As usual he has his lucky knapsack with him. The knapsack can contain k objects. There ar…
题目 Source http://codeforces.com/contest/632/problem/E Description A thief made his way to a shop. As usual he has his lucky knapsack with him. The knapsack can contain k objects. There are n kinds of products in the shop and an infinite number of pro…
Description You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least as many vases ordered in a row. The vases are glued onto the shelf and are numbered con…
Magicodes.Shop为湖南心莱信息科技有限公司(xin-lai.com)Magicodes系列产品之一. 产品中引用的Magicodes系列Nuget包的开源库地址为:https://github.com/xin-lai/ 购买地址:https://item.taobao.com/item.htm?id=539695057814 V1.2 (2016-11-19) 修改下单后,没有获取用户手机号,送货地址的信息等 后台商品类目管理,隐藏logo的显示 修复个人中心底部链接问题 新增商品评…
104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB 问题: 你想要将你的花窗安排得最具美感.有F束花,每一束花都不一样,至少有F个按顺序排成一行的花瓶.花瓶从左到右,依次编号1-V.而花放置的位置是可以改变的,花依次编号1到F.花的序号有一个特征,即是序号决定了花束出现在花瓶里的顺序.例如,有两束花编号i和j,满足i<j,那么i所在的花瓶一定要在j所在花瓶的左边,即是i…
第一节 初始目录结构 (1)初识目录结构 在创建应用之前,我们来看一下Yii 1.x版本的目录结构:将yii-1.1.13安装文件解压到网站根目录下,打开framework目录,其目录如下图所示 (2)认识framework目录 第二节 命令行创建应用~shop (1)创建应用 进入framework目录,通过如下命令行创建一个商场系统(shop) 通过如上命令创建一个商场系统(shop)后,yiitest目录下自动生成shop目录 (2)访问shop 通过如下地址即可访问刚创建的商城系统(sh…
[POJ1157]LITTLE SHOP OF FLOWERS 试题描述 You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least as many vases ordered in a row. The vases are glued onto the s…
Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 20802   Accepted: 9613 Description You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least as…
Alice's mooncake shop Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4122 Description The Mid-Autumn Festival, also known as the Moon Festival or Zhongqiu Festival is a popular harvest festival celebrated by Ch…
时间限制 30 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to…
Microsoft .NET Pet Shop 4:将 ASP.NET 1.1 应用程序迁移到 2.0 299(共 313)对本文的评价是有帮助 - 评价此主题 发布日期 : 2006-5-9 | 更新日期 : 2006-5-9 适用于:Microsoft .NET Framework 2.0Microsoft Visual Studio 2005Microsoft Windows Server 2003Microsoft InterNET Information ServicesMicroso…
B. Laurenty and Shop Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/586/problem/B Description A little boy Laurenty has been playing his favourite game Nota for quite a while and is now very hungry. The boy wants to make sa…
TIANKENG’s restaurant Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 1360    Accepted Submission(s): 545 Problem Description TIANKENG manages a restaurant after graduating from ZCMU, and tens…
asp.net的3个经典范例(ASP.NET Starter Kit ,Duwamish,NET Pet Shop)学习资料 NET Pet Shop .NET Pet Shop是一个电子商务的实例,是在Microsoft的.NET平台上的一个具体实现.NET Pet Shop 的目的是用 Microsoft .NET 实现 Sun 主要的 J2EE 蓝图应用程序 Sun Java Pet Store 同样的应用程序功能http://www.microsoft.com/china/MSDN/li…
TIANKENG’s restaurant Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 1629    Accepted Submission(s): 588 Problem Description TIANKENG manages a restaurant after graduating from ZCMU, and tens…
题目链接 E. Thief in a Shop time limit per test 5 seconds memory limit per test 512 megabytes input standard input output standard output A thief made his way to a shop. As usual he has his lucky knapsack with him. The knapsack can contain k objects. The…
题目链接:hdu 4885 TIANKENG's travel 题目大意:给定N,L,表示有N个加油站,每次加满油能够移动距离L,必须走直线,可是能够为斜线.然后给出sx,sy,ex,ey,以及N个加油站的位置,问说最少经过几个加油站,路过不加油也算. 解题思路:一開始以为经过能够不算,所以o(n2)的复杂度建图,然后用bfs求最短距离,结果被FST了. 将点依照x坐标排序,这样在建图是保证当前点为最左点,每次建立一条边的时候,将该边的斜率记录,下次有同样的斜率则不加边,斜率能够用两个整数表示,…
称号: TIANKENG's restaurant Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 249    Accepted Submission(s): 125 Problem Description TIANKENG manages a restaurant after graduating from ZCMU, and t…
最初研究 .NET Pet Shop 的目的是用 Microsoft .NET 实现 Sun 主要的 J2EE 蓝图应用程序 Sun Java Pet Store 同样的应用程序功能. 根据用 .NET 实现的 Sun J2EE 最佳实践示例应用程序,各方面的客户可以直接地对 Microsoft 的 .NET 技术与基于 J2EE 的应用程序服务器进行比较,同时了解构建基于Web的应用程序中用到的各种建议的设计模式之间的异同.旨在显示构建企业级 n 层应用程序(可能需要支持多种数据库平台和部署模…
题目链接:hdu 4122 Alice's mooncake shop 题意: 有n个订单和可以在m小时内制作月饼 接下来是n个订单的信息:需要在mon月,d日,year年,h小时交付订单r个月饼 接下来一行t,s表示制作的月饼可以保质t天,每保质一天需要花费s的价值 接下来m行表示从第0小时开始在该时间制作月饼的花费的价值 求完成所有订单消耗的最小价值. 题解: 这题我还是看了很久才看懂题意,我们将读入的订单处理后,实质就是在一个时间轴上求每个订单时间点i的t区间,也就是i-t<j<=i这个…
1056. Mice and Rice (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. Th…
C - Thief in a Shop 思路 :严格的控制好k的这个数量,这就是个裸完全背包问题.(复杂度最极端会到1e9) 他们随意原来随意组合的方案,与他们都减去 最小的 一个 a[ i ] 组合的方案数目是不会改变的 那么我们就 dp [ i ]表示 i 这个价格需要的最少 个数.  这样求最小个数保证不会漏解 然后 如果这个  i 能通过 1 - k 个物品组合出来,那么 一定能通过k 个物品组合出 i + k * a [ 1 ]. #include<bits/stdc++.h> us…
F. Shovels Shop time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are nn shovels in the nearby shop. The ii -th shovel costs aiai bourles. Misha has to buy exactly kk shovels. Each sho…
Souvenir Shop 魔幻题目,这谁搞得到啊... 考场上完全sb了写了个线段树合并,想必我是个复杂度分析都没学过的入门级选手 发现这个网格图dag它的出度最多只有2 如果按照先走朝上的一条边进行dfs走后续遍历,就是遍历完儿子再加自己,那么dfn大于它的一定不会比它低 然后再按照先走朝右的一个边走后续遍历,dfn2大于它的一定不会比它左 那么它可以到达的点满足\(\le dfn1_i,\le dfn2_i\)就可以了... 然后就是普及组随便统计一下的问题了... Code: #incl…