POJ 2411.Mondriaan's Dream 解题报告】的更多相关文章

题意: 给出n*m (1≤n.m≤11)的方格棋盘,用1*2的长方形骨牌不重叠地覆盖这个棋盘,求覆盖满的方案数. Solution:                位运算+状态压缩+dp                二进制数(####)代表填完一行后这一行的状态,填满的地方为1,未填的地方为0.                显然在填第i行时,能改变的仅为第i-1行和第i行,因此要满足在填第i行时,第1~i-2行已经全部填满.                DFS一行的状态,要是填完第i行时,…
题目链接: http://poj.org/problem?id=2411 Mondriaan's Dream Time Limit: 3000MSMemory Limit: 65536K 问题描述 Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had…
题目:Mondriaan's Dream 链接:http://poj.org/problem?id=2411 题意:用 1*2 的瓷砖去填 n*m 的地板,问有多少种填法. 思路: 很久很久以前便做过的一道题目,状压DP,当时写得估计挺艰辛的,今天搜插头DP又搜到它,就先用状压DP写了下,顺利多了,没一会就出来了,可惜因为long long没有1A. 思路挺简单,一行一行解决,每一列用1 表示对下一行有影响,用0 表示对下一行没有影响,所以一行最多2048 种可能,然后要筛选一下,因为有些本身就…
一.Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to draw on, for all of his paper was filled with squares and…
Mondriaan's Dream Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to draw on, for all of his paper was filled with squares…
Mondriaan's Dream Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 18903 Accepted: 10779 Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (…
Mondriaan's Dream Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 18903 Accepted: 10779 Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (…
Mondriaan's Dream Time Limit: 3000MS Memory Limit: 65536K Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to d…
题目链接: http://poj.org/problem?id=2411 题目意思: 给一个n*m的矩形区域,将1*2和2*1的小矩形填满方格,问一共有多少种填法. 解题思路: 用轮廓线可以过. 对每一个格子,枚举上一个格子的状态,得到当前格子的所有状态值. dp[cur][s]表示当前格子的轮廓线状态为s的情况下的总数 代码: #include<iostream> #include<cmath> #include<cstdio> #include<cstdlib…
题目:http://poj.org/problem?id=2411 Input The input contains several test cases. Each test case is made up of two integer numbers: the height h and the width w of the large rectangle. Input is terminated by h=w=0. Otherwise, 1<=h,w<=11. Output For eac…