B - Taxi（贪心） - 相关文章

【B - Taxi（贪心）】的更多相关文章

CodeForces - 158B.Taxi (贪心)

CodeForces - 158B.Taxi (贪心) 题意分析首先对1234的个数分别统计,4人组的直接加上即可.然后让1和3成对处理,只有2种情况,第一种是1多,就让剩下的1和2组队处理,另外一种是3多,那么结果就加上3的个数,再单独处理2. 对于1和2组队处理的讨论:首先分配2,有2种情况,一种是2正好分配完了,另外一种就2还剩下2个人(正好剩下1组).就一起处理这个2个人和1剩下的人. 把每次处理的结果都加起来即可. 代码 #include <iostream> #include &…

Codeforces 158 B. Taxi[贪心/模拟/一辆车最多可以坐4人同一个群的小朋友必须坐同一辆车问最少需要多少辆车]

http://codeforces.com/problemset/problem/158/B B. Taxi time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output After the lessons n groups of schoolchildren went outside and decided to visit Polyca…

B - Taxi（贪心）

Problem description After the lessons n groups of schoolchildren went outside and decided to visit Polycarpus to celebrate his birthday. We know that the i-th group consists of sifriends (1 ≤ si ≤ 4), and they want to go to Polycarpus together. They…

CodeForces 158B Taxi（贪心）

贪心,注意优先级,4单独,3与1先匹配,2与2匹配(注意判断2有没有剩下),然后2与两个1匹配,最后4个1匹配就可以了. #include<iostream> #include<cstdio> #include<cstring> using namespace std; int main() { int n; ],num; while(~scanf("%d",&n)) { memset(tot,,sizeof(tot)); ;i < n…

Codeforces 158B：Taxi

B. Taxi time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output After the lessons n groups of schoolchildren went outside and decided to visit Polycarpus to celebrate his birthday. We know that th…

P3076 [USACO13FEB]出租车Taxi

题目描述 Bessie is running a taxi service for the other cows on the farm. The cows have been gathering at different locations along a fence of length M (1 <= M <= 1,000,000,000). Unfortunately, they have grown bored with their current locations and each…

bzoj3062[Usaco2013 Feb]Taxi*

bzoj3062[Usaco2013 Feb]Taxi 题意: Bessie在农场上为其他奶牛提供出租车服务,她必须赶到这些奶牛的起始位置,并把他们带到它们的目的地.Bessie的车很小,所以她只能一次只能搭载一头奶牛.N只奶牛的起始位置和结束为止都是已知的,请确定Bessie从0点出发完成任务再到m点的最少行程.Bessie意识到,要使所得到的行程最短,Bessie可能将在沿途中让奶牛上车或下车而并不一定将一头奶牛从起点直接送到终点.n≤100000,m≤1000000000. 题解: 神贪心…