Speed Limit Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don’t know how many miles they have driven. Fortunately, Bill has a working stopwatch, so they can record their speed and the total time they have drive…

Speed Limit Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17967   Accepted: 12596 Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately…

E - Speed Limit(2.1.1) Time Limit:1000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have dr…

Speed Limit Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17030   Accepted: 11950 Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately…

Speed Limit Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17704   Accepted: 12435 Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately…

Speed Limit Time Limit: 2 Seconds      Memory Limit: 65536 KB Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately, Bill has a working stopwatch, so they can rec…

                                                                                                  Speed Limit Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17578   Accepted: 12361 Description Bill and Ted are taking a road trip. But th…

一.Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately, Bill has a working stopwatch, so they can record their speed and the total time they have dri…

http://poj.org/problem?id=2017 #include<stdio.h> int main() { int n,mile,hour; ) { ,h = ; while(n--) { scanf("%d%d",&mile,&hour); h = hour-h; sum += mile*h; h = hour; } printf("%d miles\n",sum); } ; }…

这意味着训练过程将按顺序在主流程中工作. 即:run.num_workers.   ,此外, ,因此,主进程不需要从磁盘读取数据:相反,这些数据已经在内存中准备好了. 这个例子中,我们看到了20%的加速效果,那么你可能会想,  我们考虑一个工人可能足够让队列中充满了主进程的数据,然后将更多的数据添加到队列中,不会在速度上做任何事情.我们在这里看到的就是这些, 只是我们在队列中添加了更多的批次,是否意味着这些批次的加工速度更快?因此,我们受到前向和后向传播所花费的时间的限制, 保存模型,用torc…