题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no du…

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). You are given a target value to search. If found in the array return its index, otherwise return -1.…

原题链接 题意:给你一个目标值,或者返回其在数组中的下标位置,或者返回-1(表示不存在,查找失败). 例如 0 1 2 4 5 6 7 可能成为 4 5 6 7 0 1 2. 思路分析: 用二分搜索来找到转折点,也就是最小数的位置.对二分搜索要稍作修改,当a[left]<=a[mid],可以肯定a[left...mid]是升序的,那么a[left]是最小的,也可能最小的在a[mid+1...right]中,所以要比较a[left]和min{a[mid+1...right]},同样对于a[left…

原题链接 直接贴代码,这道题是 search in rotated sorted array leetcode 的前面部分! class Solution { public: int findMin(vector<int>& nums) { if (nums.empty()) ; , nums.size()-);//好神奇,第二个参数无论减或者不减1,都不影响该题的结果 ) ; return nums[res]; } int find(vector<int>& nu…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这道是之前那道Search in Rotated Sorted Array 在旋转有序数组…

Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…

LeetCode:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, other…

题目来源 https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given…

做Leetcode题有一段时间了,但都是断断续续的,到现在才做了30题左右,感觉对自己来说还是有点难度的.希望自己能继续坚持下去,在校招前能解决超过一百题吧. 其实这些题就是用来训练你的解题思路的,做多了的话,才能在校招时面对编程题目,能立即有一个解题的流程,知道这是哪一种类型的题目,一般用什么样的套路,思路会很清晰,比如基础的字符串,数组操作会用到一些排序算法,还有一类是算法思想的题目,比如DP(动态规划),分治,回溯法,贪心等等,多练,多思考,多总结. ‘庖丁解牛,恢恢乎游刃有余’,无他,唯…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 33: Search in Rotated Sorted Arrayhttps://oj.leetcode.com/problems/search-in-rotated-sorted-array/ Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5…