[Atcoder2292] Division into Two】的更多相关文章

题目大意 给定n个不同的整数,求将它们分成两个集合X,Y,并且X集合中任意两个数的差>=A,Y集合中任意两个数的差>=B的方案数. 样例输入 5 3 7 1 3 6 9 12 样例输出 5 解析 不妨设\(A>B\),那么考虑如何动态规划.设\(f[i]\)表示第一个集合最后选择的数是i时的方案数.只用枚举第一个集合前一个选的数是哪一个即可转移.但 这么做是\(O(n^2)\)的.考虑从能够转移的点的性质出发. 对于能够转移到i的j,必须要满足的条件有 \(S_i-S_j >= A…
1.在python2 中导入未来的支持的语言特征中division(精确除法),即from __future__ import division ,当我们在程序中没有导入该特征时,"/"操作符执行的只能是整除,也就是取整数,只有当我们导入division(精确算法)以后,"/"执行的才是精确算法. 如: #python 2.7.6 Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (In…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…
Did you ever have the feeling that adding people doesn't help in software development? Did you ever think about the reason? And do you have any idea to make a change? Traditional software engineering emphasizes on division of work by modules, values…
Contestants Division   Description In the new ACM-ICPC Regional Contest, a special monitoring and submitting system will be set up, and students will be able to compete at their own universities. However there’s one problem. Due to the high cost of t…
题目传送门 /* 暴力:对于每一个数都判断,是否数字全都使用过一遍 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue> usin…
GDC2016[全境封锁(Tom Clancy's The Division)]对为何对应Eye Tracked System,以及各种优点的演讲报告 原文 4Gamer編集部:松本隆一 http://www.4gamer.net/games/241/G024173/20160317137/         北美时间2016年3月16日,在旧金山举办的Games Developers Conference 2016上,进行了关于[全境封锁(Tom Clancy's The Division)]的…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example: Given a / b =…
IMO, version 1 better than version 2, version 2 better than version 3. make some preprocess to make you code simple and efficient. Here divide the input by 2, so you don't have to do dividsion on each loop. version 1 is best thanks to http://www.cnbl…
Division 紫书入门级别的暴力,可我还是写了好长时间 = = [题目链接]uva 725 [题目类型]化简暴力 &题解: 首先要看懂题意,他的意思也就是0~9都只出现一遍,在这2个5位数中. 接着,你要知道:枚举一个5位数就够了,不用2个5位数都枚举,因为你可以通过n知道第2个5位数. 最后set维护出现的次数,ok判断是否可行,pri输出. [时间复杂度]O(1e5) &代码: #include <bits/stdc++.h> using namespace std;…