POJ 3683 Priest John's Busiest Day / OpenJ_Bailian 3788 Priest John's Busiest Day(2-sat问题) Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple w…

Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 10010   Accepted: 3425   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old l…

Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6900   Accepted: 2363   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old le…

Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples…

原题如下: Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 12162   Accepted: 4138   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an…

题目地址:POJ 3683 第一次做须要输出可行解的题目. . .大体思路是先用强连通来推断是否有可行解,然后用逆序建图.用拓扑排序来进行染色.然后输出可行解. 详细思路见传送门 由于推断的时候少写了一个等号..检查了好长时间..sad... 代码例如以下: #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <stdlib.h>…

Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11127   Accepted: 3785   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old l…

记住几个最重要的公式: xANDy=0<=>(x=>y′)AND(y=>x′) xANDy=1<=>(x′=>x)AND(y′=>y) xORy=0<=>(x=>x′)AND(y=>y′) xORy=1<=>(x′=>y)AND(y′=>x) xXORy=0<=>(x′=>y′)AND(x=>y)AND(y=>x)AND(y′=>x′) xXORy=1<=>(x=…

题意:有N场婚礼,每场婚礼的开始时间为Si,结束时间为Ti,每场婚礼有个仪式,历时Di,这个仪式要么在Si时刻开始,要么在Ti-Di时刻开始,问能否安排每场婚礼举行仪式的时间,使主持人John能参加所有的这些仪式的全过程. 题目链接:http://poj.org/problem?id=3683 ——>>每场婚礼的仪式,要么在开始段举行,要么在结束段举行,且一定要举行,要求各场婚礼仪式没冲突——>>2-SAT... 2-SAT挺神,针对此类问题,可谓手到擒来... LJ<训练指…

题意:有n对新人要在同一天结婚.结婚时间为Ti到Di,这里有时长为Si的一个仪式需要神父出席.神父可以在Ti-(Ti+Si)这段时间出席也可以在(Di-Si)-Si这段时间.问神父能否出席所有仪式,如果可以输出一组时间安排. 思路:2-SAT.神父可以在开始出席也可以在结束时候出席,要求与其他出席时间没有冲突,这样建图计算即可.另一一定要弄清楚true和false代表的含义. #include <cstdio> #include <cmath> #include <vecto…

题意: 一些人要在同一天进行婚礼,但是牧师只有1个,每一对夫妻都有一个时间范围[s , e]可供牧师选择,且起码要m分钟才主持完毕,但是要么就在 s 就开始,要么就主持到刚好 e 结束.因为人数太多了,这些时间可能会重叠,可能还会完全包含,可能还没有交叉,各种情况.问牧师能否主持完全部人的婚礼,若可以,给出每对夫妻占用牧师的一个时间段(记得按所给的夫妻的顺序哦). 主要步骤如下. (1)先建原图,不管是否会冲突. (2)找强连通分量来缩点,如果会冲突,这个时候应该发现. (3)建个缩点后,原图的…

2-SAT简单题,判断一下两个开区间是否相交 #include<cstdio> #include<cstring> #include<cmath> #include<queue> #include<vector> #include<stack> #include<algorithm> using namespace std; +; int N,M; struct Time { int Start; int End; int…

题意: $n$对$couple$举行仪式,有两个时间段可以选择,问是否可以不冲突举行完,并求方案 两个时间段选择对应一真一假,对于有时间段冲突冲突的两人按照$2-SAT$的规则连边(把不冲突的时间段连起来) 然后本题需要构造解,所以要$SCC$缩点反向建图记录否定再拓扑排序$dfs$染色,好麻烦... #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #…

这是一道裸的2-Sat,只要考虑矛盾条件的判断就好了. 矛盾判断: 对于婚礼现场 x 和 y,x 的第一段可以和 y 的第一段或者第二段矛盾,同理,x 的第二段可以和 y 的第一段或者第二段矛盾,条件是 x 的 1或2 段与 y 的 1或2 段有重合,那么选了 x 某一段就不能选择其矛盾的那一段,那就只能选择 y 中的另一段,建立一条 x (u)-> y ( v的对立 ),同理,x (u的对立)<- y ( v ) . 真的,2-sat千万不要用邻接链表!!!卡死卡死卡死!!!稠密图!!!不要…

转换成2-SAT模型,建边是如果时间(i,j)冲突就连边(i,j'),其他同理 tarjan缩点,判可行性 返图拓扑,输出方案 #include<iostream> #include<cstdio> #include<cstring> #include<vector> #include<queue> using namespace std; const int N=5005; int n,a[N],b[N],h[N],cnt,dfn[N],low…

看这个题目之前可以先看POJ2186复习一下强联通分量的分解 题意:给出N个开始时间和结束时间和持续时间三元组,持续时间可以在开始后或者结束前,问如何分配可以没有冲突. -----–我是分割线----------- 先解释一下合取范式(离散数学已经学过): 如果合取范式中的每个字句的文字个数不超过两个就称为2-SAT问题 一般性称为n-SAT问题 举个栗子:(a∨b)∧¬a" role="presentation" style="position: relative…

题目链接:http://poj.org/problem?id=3683 思路:对于每个结婚仪式,只有在开始或结束时进行这两种选择,我们可以定义xi为真当且仅当在开始时进行.于是我们可以通过时间先后确定矛盾关系,然后通过矛盾关系建图.至于输出一组可行解,就可以2次dfs(一次沿正向边,一次沿反向边)求出拓扑序,然后根据拓扑序输出可行解. http://paste.ubuntu.com/5983686/…

传送门:Problem 3683 https://www.cnblogs.com/violet-acmer/p/9769406.html 参考资料: [1]:挑战程序设计竞赛 题意: 有n场婚礼,每场婚礼有起始时间si,结束时间ti,还有一个主持仪式需要花费ti时间,ti必须安排在婚礼的开始或者结束. 主持由神父来做,但是只有一个神父,所以各个婚礼的主持时间不能重复,不过神父可以在出席完一个主持仪式后,立刻出席另一个开始时间与其结束时间相等的主持仪式,问你有没有可能正常的安排主持时间,不能输出n…

原题模型:两者(A,B)不能同时取 #include "cstdio" #include "vector" #include "stack" #include "cstring" using namespace std; #define maxn 2010 ; ]; int S[maxn],T[maxn],D[maxn],pre[maxn],sccno[maxn],lowlink[maxn],id[maxn],cfl[maxn…

发现建图的方法各有不同,前面一题连边和这一题连边建图的点就不同,感觉这题的建图方案更好. 题意:给出每个婚礼的2个主持时间,每个婚礼的可能能会冲突,输出方案. 思路:n个婚礼,2*n个点,每组点是对称的,用O(n2)的方法判断每个点之间的关系来建图,然后通过拓扑排序输出即可. 代码: #include<iostream> #include<cstdio> #include<cstring> using namespace std; #define MAXN 2002 i…

/* 2sat问题 输出任意一组可行解 */ #include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> #include<queue> #include<vector> using namespace std; #define N 2100 struct node { int u,v,next; }ff[N],bian[N*N*8]; int…

题意:一个小镇里面只有一个牧师,现在有些新人要结婚,需要牧师分别去主持一个仪式,给出每对新人婚礼的开始时间 s 和结束时间 t ,还有他们俩的这个仪式需要的时间(每对新人需要的时间长短可能不同) d ,牧师可以在婚礼开始的时间 d 内(s 到 s+d)或者是结束前的时间 d 内(t - d 到 t)完成这个仪式.现在问能否给出一种安排,让牧师能完成所有夫妇婚礼的仪式,如果可以,输出一种安排. #include <iostream> #include <cstdio> #includ…

http://poj.org/problem?id=3683 2-sat 问题判定,输出一组可行解 http://www.cnblogs.com/TheRoadToTheGold/p/8436948.html 注: 本代码在判断两个时间段部分有误,数据弱A了 #include<cstdio> #include<vector> using namespace std; #define N 1001 struct TIME { int h1,m1; int h2,m2; int tim…

题目 John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples plan to g…

Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8872   Accepted: 3027   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old le…

Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11049   Accepted: 3767   Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the…

Priest John's Busiest Day   Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God o…

Description John is the only priest in his town. October 26th is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples p…

Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples…

题目 John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples plan to g…