HDU-1719 Friend 数学推导】的更多相关文章

Mutiple  Accepts: 476  Submissions: 1025  Time Limit: 4000/2000 MS (Java/Others)  Memory Limit: 65536/65536 K (Java/Others) 问题描述 wld有一个序列a[1..n], 对于每个1≤i<n, 他希望你求出一个最小的j(以后用记号F(i)表示),满足i<j≤n, 使aj为ai的倍数(即aj mod ai=0),若不存在这样的j,那么此时令F(i) = 0 保证1≤n≤1000…
Problem Description Deep neural networks (DNN) have shown significant improvements in several application domains including computer vision and speech recognition. In computer vision, a particular type of DNN, known as Convolutional Neural Networks (…
Let’s talking about something of eating a pocky. Here is a Decorer Pocky, with colorful decorative stripes in the coating, of length L. While the length of remaining pocky is longer than d, we perform the following procedure. We break the pocky at an…
Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 556    Accepted Submission(s): 127 Special Judge Problem Description Good news for us: to release the financial pressure, the government…
Friend HDU - 1719 Friend number are defined recursively as follows. (1) numbers 1 and 2 are friend number; (2) if a and b are friend numbers, so is ab+a+b; (3) only the numbers defined in (1) and (2) are friend number. Now your task is to judge wheth…
上篇记录了一些决策树算法,这篇是借OC-SVM填回SMO在SVM中的数学推导这个坑. 参考文献: http://research.microsoft.com/pubs/69644/tr-98-14.pdf https://inst.eecs.berkeley.edu/~ee227a/fa10/login/l_dual_strong.html https://inst.eecs.berkeley.edu/~ee127a/book/login/l_sdual_slater.html http://w…
关于不同进制数之间转换的数学推导 涉及范围:正整数范围内二进制(Binary),八进制(Octonary),十进制(Decimal),十六进制(hexadecimal)之间的转换 数的进制有多种,比如两双袜子为一双就采用二进制,平常的一周七天就采用七进制,每小时有六十分钟就采用六十进制.在计算机科学中我们经常用的有二进制,八进制,十进制,十六进制.计算机只能识别0和1组成的数字,但由于当一个数字比较大的时候,二进制的长度将变得非常长,对于人来说可读性非常差,而进制越大,那么数据显示的长度便越短,…
UVA - 10014 Simple calculations Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu id=19100" style="color:blue">Submit Status Description  Simple calculations  id=19100" style="color:blue">The Pro…
sumdiv(POJ 1845) Description 给定两个自然数A和B,S为A^B的所有正整数约数和,编程输出S mod 9901的结果. Input Format 只有一行,两个用空格隔开的自然数A和B(0<=A,B<= 50000000). Output Format 只有一行,即S mod 9901的结果. Sample Input 2 3 Sample Output 15 解析 这是一道数学推导+分治的简单运用,大体思路如下. 由算数基本定理可得: \[A=p_1^{a_1}*…
本来是要调研 Latent Dirichlet Allocation 的那个 LDA 的, 没想到查到很多关于 Linear Discriminant Analysis 这个 LDA 的资料.初步看了看,觉得数学味挺浓,一时引起了很大的兴趣:再看看,就有整理一份资料的冲动了.网上查到的相关文章大都写得不是很详细,而且在概念和记号等方面也比较混乱,因此,在整理本文时,我有意识地牵了一根主线,想让读者读起来有循序渐进的感觉,记号上也力求规范和统一.期间参考了若干文献,以及一些优秀的博客,如 Jerr…