给定两个非空链表来表示两个非负整数.位数按照逆序方式存储,它们的每个节点只存储单个数字.将两数相加返回一个新的链表. 你可以假设除了数字 0 之外,这两个数字都不会以零开头. 示例: 输入:(2 -> 4 -> 3) + (5 -> 6 -> 4) 输出:7 -> 0 -> 8 原因:342 + 465 = 807 代码实现: class ListNode: def __init__(self, x): self.val = x self.next = None def…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

Python 求两个文本文件以行为单位的交集 并集 差集,来代码: s1 = set(open('a.txt','r').readlines()) s2 = set(open('b.txt','r').readlines()) print 'ins: %s'%(s1.intersection(s2)) print 'uni: %s'%(s1.union(s2)) print 'dif: %s'%(s1.difference(s2).union(s2.difference(s1)))…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

求两个列表的差集 >>> a = [1,2,3] >>> b=[1,2] >>> #################################### >>> #两个列表的差集 >>> ret = [] >>> for i in a: if i not in b: ret.append(i) >>> ret [3] >>> #两个列表的差集2 >>…

标题题目地址 1.解题意 求解两个链表的焦点,这个交点并不是焦点的值相等,而是需要交点之后的数据是完全相等的. 落实到java层面,就是交点处的对象是同一个对象即可. ps:我最开始没有读懂题目,然后就开始比较节点的值是否相等,直到示例跑失败了才知道原因. 2.通用解法 public ListNode getIntersectionNode(ListNode headA, ListNode headB) { if(headA!=null && headB!=null){ ListNode…

给定两个整数a,b,求他们的最大公约数 def gcd(a,b): if a<b: a,b=b,a while(a%b != 0): c = a%b a=b b=c return b a,b = map(int,input("请输入两个整数:").split()) #一次输入两个变量的方式 res = gcd(a,b) print(res) def gcd(a,b): if a%b == 0: return b else : gcd(b,a%b) a,b = map(int,in…

Write a program to find the node at which the intersection of two singly linked lists begins. Notice If the two linked lists have no intersection at all, return null. The linked lists must retain their original structure after the function returns. Y…

def timeInterval(self): today = datetime.date.today() print today modifiedTime = os.stat(filename).st_mtime//该文件的修改时间 modifiedTime = datetime.date.fromtimestamp(modifiedTime) //在这里转换年-月-日 格式 print modifiedTime dayCount = (today - modifiedTime).days p…