Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "-zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd-.". Now we have another string p. Your job is to find out…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/unique-substrings-in-wraparound-string/description/ 题目描述: Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so…
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…
详见:https://leetcode.com/problems/unique-substrings-in-wraparound-string/description/ C++: class Solution { public: int findSubstringInWraproundString(string p) { vector<int> cnt(26, 0); int len = 0; for (int i = 0; i < p.size(); ++i) { if (i >…
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…
2018-09-01 22:50:59 问题描述: 问题求解: 如果单纯的遍历判断,那么如何去重保证unique是一个很困难的事情,事实上最初我就困在了这个点上. 后来发现是一个动态规划的问题,可以将每个字符结尾的最长长度进行保存,这样就巧妙的解决的重复的问题. The max number of unique substring ends with a letter equals to the length of max contiguous substring ends with that…
467. Unique Substrings in Wraparound String Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Note…
