Testing the CATCHER Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 13968   Accepted: 5146 Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defensive missile calle…

Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16515 Accepted: 6082 Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defensive missile called th…

Testing the CATCHER Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 13396   Accepted: 4905 Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defensive missile calle…

Language: Default Testing the CATCHER Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15207   Accepted: 5595 Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defen…

Testing the CATCHER Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 16131   Accepted: 5924 Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defensive missile calle…

一.Description A military contractor for the Department of Defense has just completed a series of preliminary tests for a new defensive missile called the CATCHER which is capable of intercepting multiple incoming offensive missiles. The CATCHER is su…

题目大意:一种拦截导弹能拦截多枚导弹,但是它在每次拦截后高度不会再升高,给出导弹的序列,问最多能拦截多少枚导弹? 最长递减子序列问题. #include <cstdio> #include <vector> #include <algorithm> using namespace std; vector<int> m, lds; int main() { #ifdef LOCAL freopen("in", "r",…

动态规划 动态规划 容易: , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , 不易: , , , , , , , , , , , , , , , , , , , , , , , , 推荐: , , , , , , , , , , , , , , , , , , , , , , , , Jury Compromise False co…

Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. (5)构造法.(poj3295) (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法: (1)图的深度优先遍历和广度优先遍历. (2)最短路…

HDU 模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 1049 1050 1057 1062 1063 1064 1070 1073 1075 1082 1083 1084 1088 1106 1107 1113 1117 1119 1128 1129 1144 1148 1157 1161 1170 1172 1177 1197 1200 1201…