Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any oneof them. Two trees are duplicate if they have the same structure with same node values. Example 1: 1 / \ 2 3 / /…
核心思想是:序列化树 序列化后,用String可以唯一的代表一棵树,其实就是前序遍历改造一下(空节点用符号表示): 一边序列化,一边用哈希表记录有没有重复的,如果有就添加,注意不能重复添加. 重点就是序列化树,序列化得到的String可以唯一的代表一棵树,这个思想很多题都用到了 并不是只是前序遍历就能唯一表示一棵树,加上结构信息就可以了. Map<String,TreeNode> map = new HashMap<>(); List<TreeNode> res = n…
Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k. 这道题跟之前两道Contains Duplicate 包含重复值和Conta…
Question Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any one of them. Two trees are duplicate if they have the same structure with same node values. Example 1: 1 /…
Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any one of them. Two trees are duplicate if they have the same structure with same node values. Example 1: 1 / \ 2 3 / /…
Given an array of integers and an integer k, return true if and only if there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. (Old Version) Given an array of integers and an i…
Write a SQL query to delete all duplicate email entries in a table named Person, keeping only unique emails based on its smallest Id. +----+------------------+ | Id | Email | +----+------------------+ | 1 | john@example.com | | 2 | bob@example.com |…
题目标签: 题目给了我们一个 email 的table,让我们找到重复的 email. 可以建立 Person a, Person b, 找到两个表格中,emai 相等 但是 id 不同的 email, 然后利用DISTINCT 返回,因为两个表格中,会找到两个 重复的email. Java Solution: Runtime:  224 ms, faster than 40 % Memory Usage: N/A 完成日期:06/01/2019 关键点:用DISTINCT # Write yo…
题意: 如果所给序列的元素不是唯一的,则返回true,否则false. 思路: 哈希map解决. class Solution { public: bool containsDuplicate(vector<int>& nums) { unordered_map<int,int> mapp; ; i<nums.size(); i++) { if(mapp[nums[i]]) return true; ; } return false; } }; AC代码 python…
[LeetCode]652. Find Duplicate Subtrees 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/find-duplicate-subtrees/description/ 题目描述: Given a binary tree, return all duplicate sub…