奇偶排序法的思路是在数组中重复两趟扫描.第一趟扫描选择所有的数据项对,a[j]和a[j+1],j是奇数(j=1, 3, 5……).如果它们的关键字的值次序颠倒,就交换它们.第二趟扫描对所有的偶数数据项进行同样的操作(j=2, 4,6……).重复进行这样两趟的排序直到数组全部有序. public static void oddEvenSort(int[] arr){ int len = arr.length; int groupNumber = (int) Math.ceil((double)le…
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…
目录 1 问题描述 2 解决方案 1 问题描述 问题描述 输入三个数,比较其大小,并从大到小输出. 输入格式 一行三个整数. 输出格式 一行三个整数,从大到小排序. 样例输入 33 88 77 样例输出 88 77 33 2 解决方案 具体代码如下: import java.util.Scanner; public class Main { public void swap(int[] A, int a, int b) { int temp = A[a]; A[a] = A[b]; A[b]…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
