hdu 1023 hdu 1131】的更多相关文章

How Many Trees? Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1105 Accepted Submission(s): 577   Problem Description A binary search tree is a binary tree with root k such that any node v reacha…
链接:HDU 1023 /**************************************** * author : Grant Yuan * time : 2014/10/19 15:51 * source : HDU 1023 * algorithm : Catalan数+高精度 * ***************************************/ import java.io.*; import java.math.*; import java.util.*;…
最近正在学AC自动机,按照惯例需要刷一套kuangbin的AC自动机专题巩固 在网上看过很多模板,感觉kuangbin大神的模板最为简洁,于是就选择了用kuangbin大神的模板. AC自动机其实就是字典树和KMP的结合,然后去思考一下KMP的原理,然后就是在字典树上实现KMP 这里最重要的思想可能就是fail的思想,就像KMP一样,匹配失败后,有一个next的数组去回溯(最长公共前缀后缀) 如何理解了KMP的话,感觉这个不会很难理解,字典树是一个非常简单的东西就不用讲了吧. HDU - 222…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1212 Train Problem II Description As we all know the Train Problem I, the boss of the Ignatius Train Station want to know if all the trains come in strict-increasing order, how many orders that all the t…
Train Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5372    Accepted Submission(s): 2911 Problem Description As we all know the Train Problem I, the boss of the Ignatius Train Stati…
Train Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9701    Accepted Submission(s): 5210 Problem Description As we all know the Train Problem I, the boss of the Ignatius Train Stat…
Train Problem II Time Limit: 1000MS   Memory Limit: 32768KB   64bit IO Format: %I64d & %I64u Submit Status Description As we all know the Train Problem I, the boss of the Ignatius Train Station want to know if all the trains come in strict-increasing…
Train Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description As we all know the Train Problem I, the boss of the Ignatius Train Station want to know if all the trains come in strict-increasi…
题意: 给出一个数字n,假设火车从1~n的顺序分别进站,求有多少种出站序列. 思路: 卡特兰数的经典例子.n<101,用递推式解决.需要使用到大数.n=100时大概有200位以下. #include <bits/stdc++.h> using namespace std; ; vector<string> vect; void _mult(string num1, string num2, string &result ) { reverse(num1.begin()…
题意:就是问你火车出战的方案数. 分析:卡特兰数的模板题,递推公式:a[n]=a[n-1]*(4*n-2)/(n+1). java代码实现: import java.util.*; import java.math.BigInteger; import java.io.*; public class Main { public static void main(String[] args) { BigInteger a[] = new BigInteger[101]; a[0] = BigInt…