LeetCode OJ--Single Number

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[LeetCode OJ] Single Number之二 ——Given an array of integers, every element appears THREE times except for one. Find that single one.

class Solution { public: int singleNumber(int A[], int n) { ; ; ; i<=bits; i++) { ; ; ; j<n; j++) w += (A[j]>>(i-))&t; result+= (w%)<<(i-); //若是除过一个数之外,其他数重复k次,则将此处的3改为k } return result; } }; 利用二进制的位运算来解决这个问题,比如输入的数组是[2,2,3,2] 它们对应的二…

[LeetCode OJ] Single Number之一 ——Given an array of integers, every element appears twice except for one. Find that single one.

class Solution { public: int singleNumber(int A[], int n) { int i,j; ; i<n; i++) { ; j<n; j++) { if(A[j]==A[i]) { ]; A[i+] = A[j]; A[j] = temp; i++; break; } } if(j==n) return A[i]; } } }; 上面的是传统方法,时间复杂度是O(n2),空间复杂度是O(1). class Solution { public: in…

[OJ] Single Number II

LintCode 83. Single Number II (Medium) LeetCode 137. Single Number II (Medium) 以下算法的复杂度都是: 时间复杂度: O(n) 空间复杂度: O(1) 解法1. 32个计数器最简单的思路是用32个计数器, 满3复位0. class Solution { public: int singleNumberII(vector<int> &A) { int cnt[32] = {0}; int res = 0; f…

Leetcode 137 Single Number II 仅出现一次的数字

原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…

leetcode 136 Single Number, 260 Single Number III

leetcode 136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路: 如果以线性复杂度和…