题目描述 Farmer John has arranged his N (1 ≤ N ≤ 5,000) cows in a row and many of them are facing forward, like good cows. Some of them are facing backward, though, and he needs them all to face forward to make his life perfect. Fortunately, FJ recently…
题目传送门 题目描述 Farmer John has arranged his N (1 ≤ N ≤ 5,000) cows in a row and many of them are facing forward, like good cows. Some of them are facing backward, though, and he needs them all to face forward to make his life perfect. Fortunately, FJ rec…
发现选定一个长度后,怎么翻转是固定的. 那我们直接选定一个长度去操作就行. 优化操作过程 类似于堆里打持久化标记一样的感觉. [USACO07MAR]Face The Right Way G // Problem: P2882 [USACO07MAR]Face The Right Way G // Contest: Luogu // URL: https://www.luogu.com.cn/problem/P2882 // Memory Limit: 125 MB // Time Limit:…
P2882 [USACO07MAR]面对正确的方式Face The Right Way $n<=5000$?枚举翻转长度,顺序模拟就ok了 对于每次翻转,我们可以利用差分的思想,再搞搞前缀和. (输出反了还交,真菜) #include<iostream> #include<cstdio> #include<cstring> using namespace std; #define N 10010 int n,a[N],s[N],p[N],ans,mnd=1e9;…
题目链接 https://www.luogu.com.cn/problem/P2882 分析 这个题来看的话好像有点难下手,不如再去读一遍题 N遍,发现一句话很重要Each time the machine is used, it reverses the facing direction of a contiguous group of K cows in the line,就是说只能翻转固定的长度区间,那这样是不是就可以枚举区间了?枚举一层区间,再枚举每次起点,最后加上区间修改,时间复杂度\…
题目描述 Farmer John has arranged his N (1 ≤ N ≤ 5,000) cows in a row and many of them are facing forward, like good cows. Some of them are facing backward, though, and he needs them all to face forward to make his life perfect. Fortunately, FJ recently…
luogu LINK:驱逐猪猡 bzoj LINK:猪猪快跑 问题是在1时刻有个炸蛋在1号点 这个炸弹有p/q的概率爆炸 如果没有爆炸 那么会有1/di的概率选择一条边跳到另外一个点上重复这个过程. 问炸弹在第i号点上爆炸的概率. 一个比较传统的在图上期望的题目.考虑每一秒都有p/q的概率爆炸 所以当秒数过大的时候我们可以忽略不记概率了. 但是这要求需要求出每一秒炸弹在某个点的概率. 设T矩阵当前时刻炸弹在某个点的概率 显然一开始T={1,0,0,...}; 可以发现在第二秒的时候 设W矩阵为由…
题目描述 N头牛排成一列1<=N<=5000.每头牛或者向前或者向后.为了让所有牛都 面向前方,农夫每次可以将K头连续的牛转向1<=K<=N,求操作的最少 次数M和对应的最小K. 简单题意:给你一个01串,每次可以对长度为K的区间进行异或,求异或的最少次数以及对应的K. 解析: 这是一道有毒的模拟,我做了一个下午加加减减鼓捣半天都快吐(秃)了. 看到题第一反应二分答案,不过仔细一想,K和M并不相关,答案不具备单调性,无法二分出解. 所以,这道题其实是个模拟. 一个显而易见的贪心:从…
更好的阅读体验 Portal Portal1: Luogu Portal2: LibreOJ Description 在有向图\(\mathrm G\)中,每条边的长度均为\(1\),现给定起点和终点,请你在图中找一条从起点到终点的路径,该路径满足以下条件: 路径上的所有点的出边所指向的点都直接或间接与终点连通. 在满足条件\(1\)的情况下使路径最短. 注意:图\(\mathrm G\)中可能存在重边和自环,题目保证终点没有出边. 请你输出符合条件的路径的长度. Input 第一行有两个用一个…
这一节主要介绍segues,static table view cells 和 Add Player screen 以及 a game picker screen. Introducing Segues 开启 Main.storyboard拖拉一个Bar Button Item到Players窗口导航栏的右侧.在Attributes inspector中改变Identifier为Add,就会出现一个+号button.…