题目链接:Grid game 题目原文 You are given a 4x4 grid. You play a game — there is a sequence of tiles, each of them is either 2x1 or 1x2. Your task is to consequently place all tiles from the given sequence in the grid. When tile is placed, each cell which is…

1647: [Usaco2007 Open]Fliptile 翻格子游戏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 423  Solved: 173[Submit][Status][Discuss] Description Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a…

[Usaco2007 Open]Fliptile 翻格子游戏 题目 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <= M <= 15; 1 <= N <= 15) of…

问题 B: [Usaco2007 Open]Fliptile 翻格子游戏 时间限制: 5 Sec  内存限制: 128 MB 题目描述 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <=…

1647: [Usaco2007 Open]Fliptile 翻格子游戏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 702  Solved: 281[Submit][Status][Discuss] Description Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a…

问题 B: [Usaco2007 Open]Fliptile 翻格子游戏 时间限制: 5 Sec  内存限制: 128 MB 题目描述 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <=…

5972 格子游戏  时间限制: 1 s  空间限制: 128000 KB  题目等级 : 黄金 Gold   题目描述 Description Alice和Bob玩了一个古老的游戏:首先画一个n * n的点阵(下图n = 3)  接着,他们两个轮流在相邻的点之间画上红边和蓝边: 直到围成一个封闭的圈(面积不必为1)为止,“封圈”的那个人就是赢家.因为棋盘实在是太大了(n <= 200),他们的游戏实在是太长了!他们甚至在游戏中都不知道谁赢得了游戏.于是请你写一个程序,帮助他们计算他们是否结束了…

格子游戏 [问题描述] Alice和Bob玩了一个古老的游戏:首先画一个n * n的点阵(下图n = 3) 接着,他们两个轮流在相邻的点之间画上红边和蓝边:           直到围成一个封闭的圈(面积不必为1)为止,“封圈”的那个人就是赢家.因为棋盘实在是太大了(n <= 200),他们的游戏实在是太长了!他们甚至在游戏中都不知道谁赢得了游戏.于是请你写一个程序,帮助他们计算他们是否结束了游戏? [输入格式] 输入数据第一行为两个整数n和m.m表示一共画了m条线.以后m行,每行首先有两个数字…

第一步我们发现对于每一个格子,我们只有翻和不翻两种状态,我们发现一旦确定了第一行操作,那么第二行的操作也就随之确定了,因为第一行操作之后我们要想得到答案就得把第一行全部为0,那么第二行的每一个格子的操作都会对应于其上的格子的改变,而且也只有第二行能救他了.因此我们只要知道第一行的操作其他的就全都可以推知了,于是我们就用状压枚举第一行的操作,因为这是天然字典序. #include <cstdio> #include <iostream> using namespace std; ],…

题目链接:Kilani and the Game 题目原文 Kilani is playing a game with his friends. This game can be represented as a grid of size…