B. Parity Alternated Deletions Polycarp has an array aa consisting of nn integers. He wants to play a game with this array. The game consists of several moves. On the first move he chooses any element and deletes it (after the first move the array co…
http://codeforces.com/contest/1144 A. Diverse Strings A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", &qu…
A - Diverse Strings CodeForces - 1144A A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", &…
UVA.11464 Even Parity (思维题 开关问题) 题目大意 给出一个n*n的01方格,现在要求将其中的一些0转换为1,使得每个方格的上下左右格子的数字和为偶数(如果存在的话),求使得最小的转换的个数. 最先想到的是枚举每个方格的状态,非0即1,那么就有2^(n*n)种情况,可见数量之大,必定超时.那么就必须要转换思路. 不难看出这是一个开关问题,就是说可以根据一行的数据,推算出下一行的数据,然后顺次推算出整个格子的数据,之后再来看改变了多少的01序列,求出最小的结果.(稍后会演示…
题意 一个01串,可以有两种操作:①在末尾添加parity(a):②删除开头的一个字符.其中parity(a),当串中1的个数为奇数时为1,偶数时为0.问某个01串是否可以通过若干操作变成另一个01串. 思路 简单分析一下可以先发现一个事情:当一个串的1的个数为奇数时,它最多可以再增加1个1:而当1的个数是偶数时,1的个数不可能再增加.这是一个决定性的性质. 再进一步发现,奇数个数1的01串可以任意减少1的个数,以及,任意一个串可以移位.以及,当1的个数为偶数个时,可以通过在末尾任意补0以及移位…
时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 There is an integer array A1, A2 ...AN. Each round you may choose two adjacent integers. If their sum is an odd number, the two adjacent integers can be deleted. Can you work out the minimum length of the final…
1.POJ 1733 Parity game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5744   Accepted: 2233 Description Now and then you play the following game with your friend. Your friend writes down a sequence consisting of zeroes and ones. You cho…
如果sm[j]和sm[i]奇偶性相同,那么(i+1,j)个数为偶数如果奇偶性相同看成是朋友,不同的看成是敌人,那么就跟bzoj1370的做法差不多了. 如果奇偶性相同,就将x和y合并,x+n,y+n合并 如果奇偶性不同,就将x和y+n合并,y和x+n合并 #include<cstdio> #include<cstring> #include<cctype> #include<algorithm> using namespace std; #define re…
Parity game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6816   Accepted: 2636 Description Now and then you play the following game with your friend. Your friend writes down a sequence consisting of zeroes and ones. You choose a conti…
转自:http://blog.csdn.net/shahdza/article/details/7779230 [HDU]1213 How Many Tables 基础并查集★1272 小希的迷宫 基础并查集★1325&&poj1308 Is It A Tree? 基础并查集★1856 More is better 基础并查集★1102 Constructing Roads 基础最小生成树★1232 畅通工程 基础并查集★2120 Ice_cream's world I 基础并查集★212…
转自——http://blog.csdn.net/qwe20060514/article/details/8112550 =============================以下是最小生成树+并查集======================================[HDU]1213   How Many Tables   基础并查集★1272   小希的迷宫   基础并查集★1325&&poj1308  Is It A Tree?   基础并查集★1856   More i…
The Game Of Parity Solution: 这个题只需要分类讨论就可以解决. 先分别统计奇数和偶数的个数. 然后判断谁走最后一步,如果走最后一步时候同时有偶数和奇数,那么走最后一步的赢.如果没有呢,就看剩下的是奇数还是偶数,是偶数不用说,是奇数看剩奇数个还是偶数个. 针对这几种情况讨论一下就可以. #include <bits/stdc++.h> using namespace std; int n, k, o, e; int main() { cin >> n &g…
Problem Description A bit string has odd parity if the number of 1's is odd. A bit string has even parity if the number of 1's is even.Zero is considered to be an even number, so a bit string with no 1's has even parity. Note that the number of 0's d…
Description A boolean matrix has the parity property when each row and each column has an even sum, i.e. contains an even number of bits which are set. Here's a 4 x 4 matrix which has the parity property: 1 0 1 0 0 0 0 0 1 1 1 1 0 1 0 1 The sums of t…
poj1112 Team Them Up! 补图二分图+dp记录路径codeforces 256A Almost Arithmetical Progression dp或暴力 dp[i][j] = dp[j][last] + 1 ;codeforces 294C Shaass and Lights 组合 计算方法的优化codeforces 298C Parity Game 纯粹证明题,想法很好.codeforces 256D 还不会,很好的一个dppoj3417 Network LCA + 树形…
1204 Parity 题目来源: Ural 基准时间限制:1 秒 空间限制:131072 KB 分值: 80 难度:5级算法题   你的朋友写下一串包含1和0的串让你猜,你可以从中选择一个连续的子串(例如其中的第3到第5个数字)问他,该子串中包含了奇数个还是偶数个1,他会回答你的问题,然后你可以继续提问......你怀疑朋友的答案可能有错,或说同他之前的答案相互矛盾,例如:1 - 2 奇数,3 - 4 奇数,那么可以确定1 - 4 一定是偶数,如果你的朋友回答是奇数,就产生了矛盾.给出所有你朋…
POJ1733 Parity game Description Now and then you play the following game with your friend. Your friend writes down a sequence consisting of zeroes and ones. You choose a continuous subsequence (for example the subsequence from the third to the fifth…
[POJ1733]Parity game 题面 vjudge 题解 比较简单的分类并查集 将一个查询操作看作前缀和\(s_r-s_{l-1}\)的奇偶性 将每个点拆成一奇一偶然后分别连边即可 如果一个点的奇点和偶点被连在一起了就判无解即可 代码 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include…
每周日更新 2016.05.29 UVa中国麻将(Chinese Mahjong,Uva 11210) UVa新汉诺塔问题(A Different Task,Uva 10795) NOIP2012同余方程 NOIP2007统计数字 NOIP2013火柴排队 NOIP2013花匠 2016.06.05 Uva 组装电脑 12124 - Assemble Uva 派 (Pie,NWERC 2006,LA 3635) 2016.06.19 Uva 网络(Network,Seoul 2007,LA 39…
Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty  of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest  issue contains a rather inappropriate…
题目链接:http://poj.org/problem?id=1733 Parity game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9806   Accepted: 3795 Description Now and then you play the following game with your friend. Your friend writes down a sequence consisting of…
905. Sort Array By Parity (Easy)# Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: In…
P5937 [CEOI1999]Parity Game 洛谷P5937 P5937 [CEOI1999]Parity Game 前言: 个人感觉这道题初看想不到并查集啊!(说实话我题都没读懂,第二遍才读懂) 好了,转入正题,这道题我们可以用两种方法A掉:种类并查集&带权并查集 题目简述: 给定01序列的长度n,询问和答案的个数m 对于每行的询问和回答先给出两个整数,表示询问区间(闭区间) 再给出一个字符串回答:"odd"表示区间有奇数个1,"even"表示区…
题面传送门 题意:有 \(n\) 个点,每个点要么被涂黑,要么被涂白,要么没有颜色. 现在你要: 给没有颜色的点图上颜色(黑色或白色) 在这 \(n\) 个点中连若干条有向边,可以不连通.但是只能从编号小的点连向编号大的点,且不能有重边和自环. 定义一条路径 \(p_1 \to p_2 \to \dots p_k\) 是好的,当且仅当对于 \(i \in [1,k-1]\),\(c_{p_i} \neq c_p_{i+1}\). 特别地,一个点组成的路径也是好的. 求有多少种涂色+构图的方法使得…
每个标题都做了题目原网址的超链接 Day11<Given Length and Sum of Digits...> 题意: 给定一个数 m 和 一个长度 s,计算最大和最小在 s 长度下,各位数字之和为 m 的值 如果无法生成,则输出两个-1 题解: 需要注意:在输出最大值时,判一下 k 是否为 0 上板子: #include <bits/stdc++.h> using namespace std; typedef long long ll; int main() { int le…
第一题:要求产生10个随机的字符串,每一个字符串互相不重复,每一个字符串中组成的字符(a-zA-Z0-9)也不相同,每个字符串长度为10; 分析:*1.看到这个题目,或许你脑海中会想到很多方法,比如判断生成的字符串是否包含重复,在判断长度是不是10,等等. *2.其实这题我们可以培养一个习惯,大问题分解小问题解决. (1).10个字符串,我们先产生一个10个字符不重复的字符串,   (2).怎么去重复呢?集合中的HashSet就可以,这题不适合用包含方法做,代码复杂   (3).字符组成是由(a…
20170105问题解析请点击今日问题下方的"[Java每日一题]20170106"查看(问题解析在公众号首发,公众号ID:weknow619) package Jan2017; public class Ques0106 { public void method01(String... strings, int num){ } public void method02(String... strings, int... is){ } } 今日问题: 以上两个方法使用了变长参数,请问这…
20170104问题解析请点击今日问题下方的"[Java每日一题]20170105"查看(问题解析在公众号首发,公众号ID:weknow619) package Jan2017; import java.util.ArrayList; import java.util.List; public class Ques0105 { public static void main(String[] args) { List<String> list = new ArrayList…
20170103问题解析请点击今日问题下方的"[Java每日一题]20170104"查看(问题解析在公众号首发,公众号ID:weknow619) package Jan2017; import java.util.HashSet; import java.util.Set; public class Ques0104{ public static void main(String[] args){ Obj obj01 = new Obj("张三"); Obj obj…
20161230问题解析请点击今日问题下方的"[Java每日一题]20170103"查看(问题解析在公众号首发,公众号ID:weknow619) package Jan2017; public class Ques0103 { public static void main(String[] args){ System.out.println(delete("你好", "你").equals("好")); System.out…