SPOJ1812 - Longest Common Substring II(LCS2)

【SPOJ1812 - Longest Common Substring II(LCS2)】的更多相关文章

SPOJ1812 - Longest Common Substring II(LCS2)

Portal,Portal to 洛谷 Description 给出\(n(n\leq10)\)个仅包含小写字母的字符串\(s_1..s_n(|s_i|\leq10^5)\),求这些字符串的最长公共子串长度. Solution 对第一个串建立SAM,然后依次跑剩下的串. 记录\(maxL[i]\)表示对于目前做过的所有串,状态\(i\)最长能匹配的长度.跑一个串\(x\)时,记录\(tmp[i]\)表示对于串\(x\),状态\(i\)最长能匹配的长度,跑完之后将\(maxL\)与\(tmp\)取…

SPOJ1812 Longest Common Substring II

题意 A string is finite sequence of characters over a non-empty finite set Σ. In this problem, Σ is the set of lowercase letters. Substring, also called factor, is a consecutive sequence of characters occurrences at least once in a string. Now your tas…

[SPOJ1812]Longest Common Substring II 后缀自动机多个串的最长公共子串

题目链接:http://www.spoj.com/problems/LCS2/ 其实两个串的LCS会了,多个串的LCS也就差不多了. 我们先用一个串建立后缀自动机,然后其它的串在上面跑.跑的时候算出每一个位置能往左扩展的最大长度也就是LCS. 于是对于每一个状态维护mx数组,表示当前串与SAM在此状态的LCS值.对于一个状态取所有mx中的最小值,然后答案就是所有状态最小值中的最大值,证明显然. 两个串的时候不用拿一个状态更新其祖先状态,但是这里需要.SAM是一个DAG图,我们通过l数组来基数排序…

spoj1812 LCS2 - Longest Common Substring II

地址:http://www.spoj.com/problems/LCS2/ 题面: LCS2 - Longest Common Substring II no tags A string is finite sequence of characters over a non-empty finite set Σ. In this problem, Σ is the set of lowercase letters. Substring, also called factor, is a con…

SPOJ1812 LCS2 - Longest Common Substring II【SAM LCS】

LCS2 - Longest Common Substring II 多个字符串找最长公共子串以其中一个串建\(SAM\),然后用其他串一个个去匹配,每次的匹配方式和两个串找\(LCS\)一样,就是要记录\(SAM\)的每个状态和当前匹配串匹配的最大值\(maxx\),这个在匹配完一个串之后需要通过\(parent\)树上传最大匹配值,同时要更新一个最小值\(minn\),来表示每个节点和当前已经匹配过的所有串能匹配上的最大值,这个需要每次匹配一个串之后和当前节点的\(maxx\)取\(min…

SPOJ LCS2 - Longest Common Substring II

LCS2 - Longest Common Substring II A string is finite sequence of characters over a non-empty finite set Σ. In this problem, Σ is the set of lowercase letters. Substring, also called factor, is a consecutive sequence of characters occurrences at leas…