C. Writing Code time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Programmers working on a large project have just received a task to write exactly m lines of code. There are n programmers w…

题目传送门 /* 题意:n个程序员,每个人每行写a[i]个bug,现在写m行,最多出现b个bug,问可能的方案有几个 完全背包:dp[i][j][k] 表示i个人,j行,k个bug dp[0][0][0] = 1 表示不选择人的时候所有的bug的种类犯错误都只有一种 dp[i][j][k] += dp[i%2][j-1][k-a[i]]: 错误示范:dp[i][j][k] += dp[i-1][j-l][k-l*a[i]]; 其实要从上一行的状态推出,即少一行 内存限制,滚动数组使用 详细解释:…

[CF543A]/[CF544C]Writing Code 题目大意: 有\(n\)种物品,每种物品分别要\(c_i\)的代价,每个物品有\(1\)的体积,每个物品可以选多个,代价不能超过\(b\),求正好填满大小为\(m\)的背包的方案数. 思路: \(f[i][j]\)表示有\(i\)个物品,总代价为\(j\)的方案数.\(\mathcal O(n^3)\)DP即可. 源代码: #include<cstdio> #include<cctype> inline int getin…

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=99951#problem/C  (zznu14) Writing Code  Writing Code Time Limit:3000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 544C Description Programmers wo…

C. Writing Code Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/544/problem/C Description Programmers working on a large project have just received a task to write exactly m lines of code. There are n programmers working o…

有n个程序,这n个程序运作产生m行代码,但是每个程序产生的BUG总和不能超过b, 给出每个程序产生的代码,每行会产生ai个BUG,问在总BUG不超过b的情况下, 我们有几种选择方法思路:看懂了题意之后就是一个完全背包题了 定义dp[ i ][ j ][ k ] 表示前 i 个程序员,已经写了 j 行代码, 已经产生了 k 个 bugs . 根据题意,得知第 i 个程序员会写 r 行代码,那么相当于 dp[ i ][ j ][ k ] += dp[i - 1][j - r][k - ra[ i ]…

题目描述 Programmers working on a large project have just received a task to write exactly mm lines of code. There are nn programmers working on a project, the ii -th of them makes exactly a_{i}ai​ bugs in every line of code that he writes. Let's call a…

题目描述 Programmers working on a large project have just received a task to write exactly m m m lines of code. There are n n n programmers working on a project, the i i i -th of them makes exactly ai a_{i} ai​ bugs in every line of code that he writes.…

http://codeforces.com/contest/543/problem/A 一开始这题用了多重背包做,结果有后效性. 就是如果6,这样拆分成 1 + 2 + 3的,那么能产生3的就有两种情况了(同一种物品,两种情况,所以有了后效性) 分别是1 + 2 = 3和0 + 3 = 3 以前的多重背包只需要输出那些最优解,所以这个后效性可以忽略,但是现在是输出方案种类,所以不能忽视. 一开始的时候还以为他只能写b / per_bug个,因为最多b个bug,每个程序员写per_bug个.那么就…

http://codeforces.com/problemset/problem/543/A 题目大意:n个人,一共要写m行程序,每个程序员每行出现的bug数为ai,要求整个程序出现的bug数不超过b的方案数. 思路:f[i][j]代表第m行,j个bug的方案数,n^3转移 #include<cstdio> #include<cmath> #include<iostream> #include<algorithm> #include<cstring&g…

题意:有n个程序员,要协作写完m行代码,最多出现b个bug,第i个程序员每写一行代码就会产生a[i]个bug,现在问,这n个人合作来写完这m行代码,有几种方案使得出的bug总数不超过b(题中要求总方案数要对一个特定的数取模)? 分析: 这道题目属于dp中的计数类型,即求出方案数.一般来说,为了求出方案数,要将现存的问题分为2个或2个以上完全不重叠的子问题.这就类似于,有n层楼梯,你可以一次跨1阶,或者一次跨2阶,问你有多少种上楼梯的方法一样. 在上楼梯问题中,我们可以在当前状态的第一步跨上1阶,…

题意:现在要写m行代码,总共有n个文件,现在给出第i个文件每行会出现v[i]个bug,问你在bug少于b的条件下有多少种安排 分析:定义dp[i][j][k],i个文件,用了j行代码,有k个bug 状态转移为 1.在第i个文件,不写代码   dp[i][j][k]=dp[i-1][j][k] 2.在第i个文件,写代码      dp[i][j][k]+=dp[i][j-1][k-v[i]] 这题巧妙在于,既往i转移,又往j和k方向转移,这样我把它形容为二维动态规划 代码: #include <b…

本博客参考自这里 不是我说,我就觉得这题题目贼鸡儿难懂 所以只能看看别的博客如何解释这题题目的意思咯. 有n个程序,这n个程序运作产生m行代码,但是每个程序产生的BUG总和不能超过b,给出每个程序产生的代码,每行会产生ai个BUG,问在总BUG不超过b的情况下,我们有几种产生bug的方法.解释一下例一的几种情况我用1,2,3代表程序,然后每个都是1个bug就不需要特地其他方法搞 一共十种情况然后对dp进行分析,设立一个dp[j][k],j代表代码数m,k代表bug数b然后写状态转移方程:dp[j…

程序员写bug的故事23333 题意:n个程序员,一共写m行程序,最多产生b个bug,问方案数 思路:f[i][j]表示写了i行,产生了j个bug的方案数,因为每个人都是可以独立的,所以i循环到n都做一遍 f[i][j] += f[i-1][j-a[i]] 在前一行  i 的 a[i] 个bug还没有写上去的情况数 #include <iostream> #include <cstdio> #include <algorithm> using namespace std…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 二维费用背包. f[i][j][k] 前i个人,写了j行,bug不超过k的方案数. 可以把每个人看成是一个物品. 它可以无限拿.然后花费为 1行代码和a[i]个bug (拿几个第i个人就相当于v[i]等于几. 就变成一个二维的完全背包了 直接用二维费用背包的方案数求法求得就好 两维的写法比三维的写法简单..直接顺序更新就可以了 (顺序更新) [代码] #include <bits/stdc++.h> using namespa…

Error handling is important, but if it obscures logic, it's wrong. Use Exceptions Rather Than Return Codes Separate the normal operations with error handlings. e.g. Bad code: public class DeviceController { ... public void sendShutDown() { DeviceHand…

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I am lucky enough to work with a small team of fantastic engineers who truly care about their customers. If you are not that lucky, this letter is for you to share with your engineering team. Dear Engineers, Your job is not to write code. I know. You…

Let’s learn by example. Throughout this tutorial, we’ll walk you through the creation of a basic poll application. It’ll consist of two parts: A public site that lets people view polls and vote in them. An admin site that lets you add, change and del…

注: 以下内容引自: https://blogs.msdn.microsoft.com/ericlippert/2004/06/14/reading-code-is-hard/ Reading Code Is Hard ★★★★★ ★★★★ ★★★ ★★ ★   Eric LippertJune 14, 200426 Share 0 0 Escalation Engineer JeremyK asks in his blog this morning: how do you teach peop…

原文:https://www.webcodegeeks.com/web-development/clean-code-principles-better-programmer/ ----------------------------------------------------------------- “My code is working well, the website I built is looking great, and my client is happy. So why…

This topic demonstrates how to create a simple XAF application with a business model in a DbContext context. 本主题演示如何在 DbContext 上下文中使用业务模型创建简单的 XAF 应用程序. Note 注意 This topic demonstrates the code that can be generated automatically by the Solution Wiz…

SQL Server Reporting Services versions 2000 and 2005 (SSRS) has many powerful features. SSRS has a well-designed data access engine, a great set of layout tools, and an excellent expression system for creating complex formulas. While the expression s…

Simple Code! 简洁编码 Playing football is very simple, but playing simple football is the hardest thing there is. - Johan Cruyff 踢足球非常简单,但踢简单的足球是最难的事情.- Johan Cruyff If we take this famous quote for programming, we can say; 如果我们把这句名言用于编程,我们也可以说: Writing…

Awesome系列的.Net资源整理.awesome-dotnet是由quozd发起和维护.内容包括:编译器.压缩.应用框架.应用模板.加密.数据库.反编译.IDE.日志.风格指南等. 算法与数据结构(Algorithms and Data structures) Algorithmia - Algorithm and data-structure library for .NET 3.5 and up. Algorithmia contains sophisticated algorithms…

"Life is short, you need Python!" Python (British pronunciation:/ˈpaɪθən/ American pronunciation:/ˈpaɪθɑːn/)), is an object-oriented computer programming language, literal translation, with nearly 20 years of development history. It contains a s…

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大体上是把官网上的翻译下而已. http://www.ninject.90iogjkdcrorg/wiki.html Dependency Injection By Hand So what's Ninject all about? First, let's examine the idea of dependency injection by walking through a simple example. Let's say you're writing the next blockbus…

How To Determine the .NET Framework Installed Versions This topic is a how to.Please keep it as clear and simple as possible. Avoid speculative discussions as well as a deep dive into underlying mechanisms or related technologies. Table of Contents  …