219 Contains Duplicate II 存在重复 II】的更多相关文章

给定一个整数数组和一个整数 k,判断数组中是否存在两个不同的索引 i 和 j,使 nums [i] = nums [j],并且 i 和 j 的绝对差值最大为 k. 详见:https://leetcode.com/problems/contains-duplicate-ii/description/ Java实现: class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { int n=nums.leng…
Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input: nums = [1,2,3,1], k = 3 Output:…
原文题目: 217. Contains Duplicate 219. Contains Duplicate II 读题: 217只要找出是否有重复值, 219找出重复值,且要判断两者索引之差是否小于k //217. Contains Duplicate 46ms class Solution { public: bool containsDuplicate(vector<int>& nums) { set <int> s; //vector <int>::ite…
 217 - Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Solution 1: s…
219. Contains Duplicate II[easy] Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 错误解法: class Solut…
Question 219. Contains Duplicate II Solution 题目大意:数组中两个相同元素的坐标之差小于给定的k,返回true,否则返回false 思路:用一个map记录每个数的坐标,如果数相同,如果坐标差小于k则返回true否则覆盖,继续循环 Java实现: public boolean containsNearbyDuplicate(int[] nums, int k) { Map<Integer, Integer> map = new HashMap<&…
Given an array of integers, find out whether there are two distinct indices i and j in the array such that the absolute difference between nums[i] and nums[j] is at most t and the absolute difference between i and j is at most k. Example 1: Input: nu…
Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k. 这道题跟之前两道Contains Duplicate 包含重复值和Conta…
Leetcode之回溯法专题-90. 子集 II(Subsets II) 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集). 说明:解集不能包含重复的子集. 示例: 输入: [1,2,2] 输出: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 分析:是78题的升级版,新增了一些限制条件,nums数组是会重复的,求子集. class Solution { List<List<Integer>> ans = new Arr…
Leetcode之回溯法专题-47. 全排列 II(Permutations II) 给定一个可包含重复数字的序列,返回所有不重复的全排列. 示例: 输入: [1,1,2] 输出: [ [1,1,2], [1,2,1], [2,1,1] ] 分析:跟46题一样,只不过加了一些限制(包含了重复数字). AC代码(时间复杂度比较高,日后二刷的时候改进): class Solution { List<List<Integer>> ans = new ArrayList<>()…