POJ 3650:The Seven Percent Solution】的更多相关文章

The Seven Percent Solution Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7684   Accepted: 5159 Description Uniform Resource Identifiers (or URIs) are strings like http://icpc.baylor.edu/icpc/, mailto:foo@bar.org, ftp://127.0.0.1/pub/li…
The Seven Percent Solution Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1680    Accepted Submission(s): 1215 Problem Description Uniform Resource Identifiers (or URIs) are strings like http:/…
The Seven Percent Solution Time Limit: 2 Seconds      Memory Limit: 65536 KB Uniform Resource Identifiers (or URIs) are strings like http://icpc.baylor.edu/icpc/, mailto:foo@bar.org, ftp://127.0.0.1/pub/linux, or even just readme.txt that are used to…
Problem Description Uniform Resource Identifiers (or URIs) are strings like http://icpc.baylor.edu/icpc/, mailto:foo@bar.org, ftp://127.0.0.1/pub/linux, or even just readme.txt that are used to identify a resource, usually on the Internet or a local…
#include <cstdio> #include <cstring> int main() { ]; ]!='#') { ; while (i<strlen(s)) { if (s[i]==' ') printf("%s","%20"); else if (s[i]=='!') printf("%s","%21"); else if (s[i]=='$') printf("%s&qu…
题意:把字符串中的一些特殊符号用给定的字符串代替. 析:没的说. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <queue> #include <vector> #include <cstring> #include <map> using namespace std; const int maxn = 100; cha…
连环锁 Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 1260   Accepted: 403 Description 许多人一定很熟悉九连环(如下图),九个环被串在一起,操作规则如下:第一个(右边)环可以任意装卸,如果第k个环没有被卸掉,而第k个环前边(右边)的所有环都被卸掉,则第k+1个环(第k个环左边的环)可以任意装卸(如果存在的话). 用0表示此换被卸掉,1表示此环没有被卸掉,则九连环的每个状态可以用一个长度为9…
题面: 传送门:http://poj.openjudge.cn/practice/1009/ Solution DP+DP 首先,我们可以很轻松地求出所有物品都要的情况下的选择方案数,一个简单的满背包DP就好 即:f[i][j]表示前i个物品装满容量为j的背包的方案数. 转移也很简单 f[i][j]=f[i-1][j]+f[i-1][j-w[i]] (i:1~n,j:1~m) (即选和不选的问题) 初始化 f[i][0]=1 (i:[0~n]) (如果背包容量为0,无论如何都有且只有一种方案将其…
Stars in Your Window Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11706   Accepted: 3183 Description Fleeting time does not blur my memory of you. Can it really be 4 years since I first saw you? I still remember, vividly, on the beaut…
HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…