Permutation Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 114    Accepted Submission(s): 67Special Judge Problem Description There are two sequences h1∼hn and c1∼cn. h1∼hn is a permutatio…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 133    Accepted Submission(s): 84 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he marke…

Sqrt Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 145    Accepted Submission(s): 72 Problem Description Let's define the function f(n)=⌊n−−√⌋. Bo wanted to know the minimum number y whic…

Swipe Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1549    Accepted Submission(s): 315 Problem Description "Swipe Bo" is a puzzle game that requires foresight and skill.  The main ch…

Sqrt Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5752 Description Let's define the function f(n)=⌊n−−√⌋. Bo wanted to know the minimum number y which satisfies fy(n)=1. note:f1(n)=f(n),fy(n)=f(fy−1(n)) It is a pity that Bo can only use 1 unit…

Permutation Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5753 Description There are two sequences h1∼hn and c1∼cn. h1∼hn is a permutation of 1∼n. particularly, h0=hn+1=0. We define the expression [condition] is 1 when condition is True,is 0 whe…

Teacher Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 Description Teacher BoBo is a geography teacher in the school.One day in his class,he marked N points in the map,the i-th point is at (Xi,Yi).He wonders,whether there is a tetrad (A,B,C,…

Life Winner Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5754 Description Bo is a "Life Winner".He likes playing chessboard games with his girlfriend G. The size of the chessboard is N×M.The top left corner is numbered(1,1) and the lower r…

Sqrt Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2221    Accepted Submission(s): 882 Problem Description Let's define the function f(n)=⌊n−−√⌋. Bo wanted to know the minimum number y wh…

Rower Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5761 Description There is a river on the Cartesian coordinate system,the river is flowing along the x-axis direction. Rower Bo is placed at (0,a) at first.He wants to get to origin (0,0) by boa…

Teacher Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 Description Teacher BoBo is a geography teacher in the school.One day in his class,he marked N points in the map,the i-th point is at (Xi,Yi).He wonders,whether there is a tetrad (A,B,C,…

Permutation Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5753 Description There are two sequences h1∼hn and c1∼cn. h1∼hn is a permutation of 1∼n. particularly, h0=hn+1=0. We define the expression [condition] is 1 when condition is True,is 0 whe…

Sqrt Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5752 Description Let's define the function f(n)=⌊n−−√⌋. Bo wanted to know the minimum number y which satisfies fy(n)=1. note:f1(n)=f(n),fy(n)=f(fy−1(n)) It is a pity that Bo can only use 1 unit…

Life Winner Bo Problem Description   Bo is a "Life Winner".He likes playing chessboard games with his girlfriend G. The size of the chessboard is N×M.The top left corner is numbered(1,1) and the lower right corner is numberd (N,M). For each game…

传送门 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Special Judge Problem DescriptionThere is a river on the Cartesian coordinate system,the river is flowing along the x-axis direction. Rower Bo is placed at $(0,a…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1014    Accepted Submission(s): 561 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he mar…

1010 Rower Bo 首先这个题微分方程强解显然是可以的,但是可以发现如果设参比较巧妙就能得到很方便的做法. 先分解v_1v​1​​, 设船到原点的距离是rr,容易列出方程 \frac{ dr}{ dt}=v_2\cos \theta-v_1​dt​​dr​​=v​2​​cosθ−v​1​​ \frac{ dx}{ dt}=v_2-v_1\cos \theta​dt​​dx​​=v​2​​−v​1​​cosθ 上下界都是清晰的,定积分一下: 0-a=v_2\int_0^T\cos\thet…

这里是一个比较简单的问题:考虑每个数对和的贡献.先考虑数列两端的值,两端的摆放的值总计有2种,比如左端:0,大,小:0,小,大:有1/2的贡献度.右端同理. 中间的书总计有6种可能.小,中,大.其中有两种对答案有贡献,即1/3的贡献度.加和计算可得到答案. Permutation Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s):…

Sqrt Bo Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 980    Accepted Submission(s): 452 Problem Description Let's define the function f(n)=⌊n√⌋. Bo wanted to know the minimum number y which…

http://acm.hdu.edu.cn/showproblem.php?pid=5755 题意:一个N*M的矩阵,改变一个格子,本身+2,四周+1.同时mod 3;问操作多少次,矩阵变为全0.输出次数和具体位置 由于影响是相互的,所以增广矩阵的系数a[t][t+1] 或者是 a[t+1][t]均可:只需注意往结果中添加位置时,x[i]表示要操作x[i]次,所以位置要重复添加x[i]次: 高斯消元时间复杂度为O(N3M3); #pragma comment(linker, "/STACK:10…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 752    Accepted Submission(s): 412 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he mark…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5754 给你四种棋子,棋子一开始在(1,1)点,两个人B和G轮流按每种棋子的规则挪动棋子,棋子只能往右下方移动,谁最后先挪动棋子到(n,m)位置,谁就胜利.要是两个人都不可能赢,就输出D. king的情况在纸上模拟了一下,感觉就是当n*m为奇数时先手输,否则就赢. rook的情况比较简单,相当于在两堆石子中取石子,只能在一堆中取.当n等于m时,先手必败,因为先手怎么取,后手都会跟上取 使得两堆石子相同…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5761 题目大意: 船在(0,a),船速v1,水速v2沿x轴正向,船头始终指向(0,0),问到达(0,0)用时,无解输出Infinity. 题目思路: [数学] 说是数学其实更像物理. 很明显v1<=v2时无解. 这道题列积分方程然后解出来式子是t=a*v1/(v12-v22). 我列积分方程的时候少了一个式子没解出来. 可以看看半根毛线的.http://images2015.cnblogs.com…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5754 题目大意: 4种棋子,象棋中的 1王,2车,3马,4后,选其一,B和G轮流走,不能往左上走,一开始棋子在(1,1),谁先走到(n,m)谁赢,无法走动算平局D. (n,m<=1000,case<=1000) 题目思路: [博弈论] 这题博弈论.怎样都输为必败,只能走到必败的为必胜. 王:(王可以横竖斜走一格)如果n个m均为奇数先手必败,否则必胜. 从3x3格子看,当n和m均为奇数时先手必败,…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 题目大意: 给n个点,坐标范围0~m(n,m<=105),求是否存在2个点对满足哈夫曼距离相等. 题目思路: [模拟] 乍一看n2绝对T了,但是细想之下发现,坐标范围只有105,那么哈夫曼距离最多就2x105种,所以当循环超出这个范围时肯定能找到解(抽屉原理). // //by coolxxx // #include<iostream> #include<algorithm&g…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5752 题目大意: 定义f(n)=⌊√n⌋,fy(n)=f(fy-1(n)),求y使得fy(n)=1.如果y>5输出TAT.(n<10100) 题目思路: [模拟] 5层迭代是232,所以特判一下层数是5的,其余开根号做.注意数据有0. 队友写的. #include<stdio.h> #include<string.h> #include<math.h> int…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5753 题目大意: 两个序列h和c,h为1~n的乱序.h[0]=h[n+1]=0,[A]表示A为真则为1,假为0. 函数f(h)=(i=1~n)∑ci[hi>hi−1 && hi>hi+1] 现在给定c的值,求f(h)的期望. 题目思路: [数学] 头尾的概率为1/2,中间的概率为1/3,直接求和. // //by coolxxx // #include<iostream&g…

[题目链接] http://acm.hdu.edu.cn/showproblem.php?pid=5755 [题目大意] 一个n*m由0,1,2组成的矩阵,每次操作可以选取一个方格,使得它加上2之后对3取模,周围的四个方格加上1后对3取模,请你在n*m操作次数内让整个矩阵变成0.输出一种方案. [题解] 枚举第一行的方式显然是不行的,因为3的30次方显然不是可以承受的范围,考虑如果存在第0行元素,那么这一行的最终状态就是第一行的操作次数,因为每个格子很明显只会由第一行对应的正下方的格子影响,我们…

[题目链接] http://acm.hdu.edu.cn/showproblem.php?pid=5758 [题目大意] 给出一棵树,每条路长度为1,允许从一个节点传送到任意一个节点,现在要求在传送次数尽量少的情况下至少经过每条路一遍啊,同时最小化走过的路程总长度.输出路程总长度. [题解] 首先,对于传送次数尽量少这个条件,我们很容易发现,当且仅当每次出发点和终止点都是叶节点的时候,是最少的,当然在叶节点无法两两匹配的时候,再多走一条链. 然后就是叶节点的匹配问题,使得匹配后的叶节点连线覆盖全…

http://acm.hdu.edu.cn/showproblem.php?pid=5754 题意: 给一个国际象棋的棋盘,起点为(1,1),终点为(n,m),现在每个棋子只能往右下方走,并且有4种不同的棋子,棋子的走法与国际象棋走法一致.问最后谁能取得胜利. 思路: 首先推荐一个博客http://www.matrix67.com/blog/archives/6784,这里面对这问题有很好的讲解. 我还是简单解释一下: ①king: 国王每次只能横.竖.斜走一格,这个很好分析,(x,y)如果连个…