http://acm.hdu.edu.cn/showproblem.php?pid=4561 求连续最大积. 他妈的狗逼思路到底咋说..... 思路是 %&*()*(&--))*)*&)--%--%**(*()()--+(**(--&*--%&*--Y%^&%%^*&&(&*(&*(*&()*&(**--&%--& %&--%&--&(&--* ())&(…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 89984    Accepted Submission(s): 21437 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

超级楼梯 Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description 有一楼梯共M级,刚开始时你在第一级,若每次只能跨上一级或二级,要走上第M级,共有多少种走法? Input 输入数据首先包含一个整数N,表示测试实例的个数,然后是N行数据,每行包含一个整数M(<=M<=),表示楼梯的级数. Outpu…

Friendship of Frog Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5578 Description N frogs from different countries are standing in a line. Each country is represented by a lowercase letter. The distance betwee…

ZYB's Biology Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5590 Description ZYB(ZJ−267)在NOIP拿到600分之后开始虐生物题,他现在扔给你一道简单的生物题:给出一个DNA序列和一个RNA序列,问它们是否配对. DNA序列是仅由A,C,G,T组成的字符串,RNA序列是仅由A,C,G,U组成的字符串. DNA和RNA匹配当且仅当每…

L - House Building Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5538 Description Have you ever played the video game Minecraft? This game has been one of the world's most popular game in recent years. The wor…

Big Number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21106    Accepted Submission(s): 9498 Problem Description In many applications very large integers numbers are required. Some of these…

Problem Description You may have heard of the book '2001 - A Space Odyssey' by Arthur C. Clarke, or the film of the same name by Stanley Kubrick. In it a spaceship is sent from Earth to Saturn. The crew is put into stasis for the long flight, only tw…

Problem Description 妈妈每天都要出去买菜,但是回来后,兜里的钱也懒得数一数,到底花了多少钱真是一笔糊涂帐.现在好了,作为好儿子(女儿)的你可以给她用程序算一下了,呵呵. Input 输入含有一些数据组,每组数据包括菜种(字串),数量(计量单位不论,一律为double型数)和单价(double型数,表示人民币元数),因此,每组数据的菜价就是数量乘上单价啊.菜种.数量和单价之间都有空格隔开的. Output 支付菜价的时候,由于最小支付单位是角,所以总是在支付的时候采用四舍五入的…

Problem Description 8600的手机每天消费1元,每消费K元就可以获赠1元,一开始8600有M元,问最多可以用多少天? Input 输入包括多个测试实例.每个测试实例包括2个整数M, k,(2 <= k <= M <= 1000).M = 0, k = 0代表输入结束. Output 对于每个测试实例输出一个整数,表示M元可以用的天数. Sample Input 2 2 4 3 0 0 Sample Output 3 5 水题.... import java.util.…

本来是不打算贴这道水题的,自己却WA了三次.. 要考虑1的情况,1的质因子为1 思路:先打表 ,然后根据最大质因子更新结果 代码: #include<iostream> #include<cstdlib> #include<cstdio> #include<cstring> using namespace std; #define MAX 20000 int p[MAX]; int main() { memset(p,,sizeof(p)); p[]=; ;…

题意:中文...你们懂得. 析:这个就是一个水题博弈,就是一个巴什博弈定理,直接就没有变,如果你们看过我写的那个,这个题绝对水过. 附地址:http://www.cnblogs.com/dwtfukgv/p/5517818.html 看完后就懂了吧,不用说了,直接上代码就OK. 代码如下: #include <iostream> #include <string> #include <vector> #include <algorithm> #include…

Building bridges Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 45    Accepted Submission(s): 39 Problem Description Hululu and Cululu are two pacific ocean countries made up of many islands. T…

R(N) Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1815    Accepted Submission(s): 929 Problem Description We know that some positive integer x can be expressed as x=A^2+B^2(A,B are integers).…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10423    Accepted Submission(s): 4287 Problem Description There is a pile of n wooden sticks. The length and weight of each stick ar…

链接:传送门 思路:水题略 /************************************************************************* > File Name: hdu2078.cpp > Author: WArobot > Blog: http://www.cnblogs.com/WArobot/ > Created Time: 2017年04月30日 星期日 23时47分30秒 *****************************…

Switch Game Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13113    Accepted Submission(s): 7970 Problem Description There are many lamps in a line. All of them are off at first. A series of o…

Almost Sorted Array Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 8541    Accepted Submission(s): 1982 Problem Description We are all familiar with sorting algorithms: quick sort, merge sort…

题目链接: 传送门 最大连续子序列 Time Limit: 1000MS     Memory Limit: 32768 K Description 给定K个整数的序列{ N1, N2, ..., NK },其任意连续子序列可表示为{ Ni, Ni+1, ..., Nj },其中 1 Input 测试输入包含若干测试用例,每个测试用例占2行,第1行给出正整数K( Output 对每个测试用例,在1行里输出最大和.最大连续子序列的第一个和最后一个元 素,中间用空格分隔.如果最大连续子序列不唯一,则…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4813 签到题. 把一个字符串按照格式输出就可以了,很水 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <queue> #include <map> #include <set> #include…

ZYB loves Score Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5268 Description One day,ZYB participated in the BestCoder Contest There are four problems. Their scores are 1000,1500,2000,2500 According to the r…

A Sweet Journey Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5477 Description Master Di plans to take his girlfriend for a travel by bike. Their journey, which can be seen as a line segment of length L, is a r…

Equations 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1840 ——每天在线,欢迎留言谈论. 题目大意: 给你一个一元二次方程组,a(X^2) + b(X) + c = 0 .求X解的个数. 思路: 分别讨论二次方程与一次方程的情况,再特殊处理下 a = b = c = 0 的情况. 感想: 是时候该水水题了. Java AC代码: import java.math.*; import java.util.Scanner; public…

http://acm.hdu.edu.cn/showproblem.php?pid=5104 找元组数量,满足p1<=p2<=p3且p1+p2+p3=n且都是素数 不用素数打表都能过,数据弱的一比 #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <queue> #inclu…

摘自题解: 题意转化一下就是: 给出一列数a[1]...a[n],求长度最长的一段连续的数,使得这些数的和能被M整除. 分析: 设这列数前i项和为s[i], 则一段连续的数的和 a[i]+a[i+1]+...+a[j-1]+a[j]=s[j]-s[i-1], 所以这段连续的数的和能被m整除的条件就是 (s[j]-s[i-1]) % m == 0, 即 s[j]%m-s[i-1]%m == 0, 因此,只需要每一个余数找使s[i]%m等于该余数的最小的i,和s[j]%m等于该余数的最大的j,相减即…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1062 解题报告:注意一行的末尾可能是空格,还有记得getchar()吃回车符. #include<cstdio> #include<string.h> #include<iostream> #include<algorithm> #include<cmath> #include<deque> #include<cstdlib>…

其实如果想出了方法真的好水的说... 然而一开始想了好久都没想出来... 最后看了一下最大数据才32768 可以直接枚举...枚举每个硬币的数量 看看后来能不能凑够n 因为还是怕超时..(虽然只有3乘十的四次方)所以先枚举三分 然后二分 最后一分肯定足够 就不用了 自己好傻... #include<stdio.h> #include<string.h> #include<algorithm> #include<map> #include<math.h&…

题意: 给一个序列,要找一个等差或等比的连续子序列,求其最长的长度. 思路: 扫两遍,判断等差或等比即可.从左往右扫,维护一个滑动窗口,考虑新加进来的数,如果满足了要求,则更新长度,否则只留最后两个数字,其他删掉,接着继续考虑下一个数字.等比也是如此,只是要注意精度的问题. 别人的代码: #include <bits/stdc++.h> using namespace std; ; int arr[MAX]; int main(void) { //freopen("in.txt&qu…

Dylans loves numbers Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5272 Description Dylans是谁?你可以在 UOJ 和 Codeforces上看到他.在BestCoder里,他有另外一个ID:s1451900.今天的题目都和他有关哦.Dylans得到了一个数N.他想知道N的二进制中有几组1.如果两个1之间有若干个(至少一个)0…

A Curious Matt Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5112 Description There is a curious man called Matt. One day, Matt's best friend Ted is wandering on the non-negative half of the number line. Matt f…