要求 非空数组的所有数字都是正整数,是否可以将这个数组的元素分成两部分,使得每部分的数字和相等 最多200个数字,每个数字最大为100 示例 [1,5,11,5],返回 true [1,2,3,5],返回 false 思路 在n个物品中选出一定物品,填满sum/2的背包 状态:F(n,C) 转移:F(i,c)=F(i-1,c) || F(i-1,c-w(i)) 复杂度:O(n*sum/2) = O(n*sum) 实现 递归+记忆化搜索(归纳法) 16-17:是否计算过 1 class Solut…

lc 416 Partition Equal Subset Sum 416 Partition Equal Subset Sum Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of th…

Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Both the array size and each of the array element will not exceed 100. Exam…

Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100. The array size will not exce…

题目: Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Both the array size and each of the array element will not exceed 100.…

Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100. The array size will not exce…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS 动态规划 日期 题目地址:https://leetcode.com/problems/partition-equal-subset-sum/description/ 题目描述 Given a non-empty array containing only positive integers, find if the array can be…

题目 Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100. The array size will not e…

详见:https://leetcode.com/problems/partition-equal-subset-sum/description/ C++: class Solution { public: bool canPartition(vector<int>& nums) { int sum = accumulate(nums.begin(), nums.end(), 0); if (sum % 2 == 1) { return false; } int target = sum…

题目如下: 解题思路:对于这种判断是否的题目,首先看看动态规划能不能解决.本题可以看成是从nums中任选i个元素,判断其和是否为sum(nums)/2,很显然从nums中任选i个元素的和的取值范围是[0,sum(nums)],这里就可以用一个dp数组来保存nums中任选i个元素的和的取值的和,记dp[v] = 1表示可以从nums中任选i个元素使得其和等于v,dp[v] = 0 则表示不可以.那么nums中任意元素nums[i]来说,只要找出dp[0,sum(nums[0:i-1])] 中所有为…