869. 重新排序得到 2 的幂 枚举排列,然后验证.比较暴力. 其实好一点的做法应该反过来,先把int范围下的2的N幂算出来,然后一个一个验证给出的数能不能拼成. class Solution { public Integer[] nextPermutation(Integer[] nums) { if (nums.length == 1) { return new Integer[]{}; } int p = -1; for (int i = nums.length - 2; i >= 0;…
Starting with a positive integer N, we reorder the digits in any order (including the original order) such that the leading digit is not zero. Return true if and only if we can do this in a way such that the resulting number is a power of 2. Example…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典统计每位数字出现的次数 日期 题目地址:https://leetcode.com/problems/reordered-power-of-2/description/ 题目描述 Starting with a positive integer N, we reorder the digits in any order (including the…