题目链接:http://codeforces.com/gym/101873/problem/K 题意: 现在给出 $n(1 \le n \le 1e4)$ 个员工,最多可以裁员 $k$ 人,名字为 $s_i$ 的员工的薪资为 $c_i(1 \le c_i \le 1e5)$. 已知必须节省下 $d(1 \le d \le 1e9)$ 元才能拯救公司,问要裁员哪些人. 题解: 薪资越高的人越要裁掉. (这么个大水题,居然没人发现,交的人不多.可能是这套题英语阅读量有点烦人吧……) AC代码: #i…

L. Ministry of Truth Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100187/problem/K Description Andrey works in the Ministry of Truth. His work is changing articles in newspapers and magazines so that they praise the Party an…

LINK 题意:给出1~n数字的排列,求变为递增有序的最小交换次数 思路:水题.数据给的很小怎么搞都可以.由于坐标和数字都是1~n,所以我使用置换群求循环节个数和长度的方法. /** @Date : 2017-07-20 14:45:30 * @FileName: LightOJ 1166 贪心 或 置换群 水题.cpp * @Platform: Windows * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github…

本文含有原创题,涉及版权利益问题,严禁转载,违者追究法律责任 本次是最后一篇免费的考试题解,以后的考试题目以及题解将会以付费的方式阅读,题目质量可以拿本次作为参考 本来半个月前就已经搞得差不多了,然后给一位神犇orz看(神犇orz都是很忙的!),就一直听取意见修修改改呀拖到了半个月之后,不过这也是为了能够做到完美吧 T1-apple-1s 第一题是一道贪心的水题 天数只有两天,不是今天吃就是明天吃,我们将 b[i]=min(x[i],y[i])定为基础开心值,也就是说不论哪天吃都至少可以得到这个…

http://cojs.tk/cogs/problem/problem.php?pid=714 在hzwer的刷题记录上,默默地先跳过2题T_T...求凸包和期望的..T_T那是个啥..得好好学习 看到这题,. 太水了. 按价值排序后计算即可.(本来不想放题解的,但是为了满足下自己的虚荣心吧) #include <cstdio> #include <cstring> #include <cmath> #include <string> #include &l…

Problem E. Explicit Formula Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100610 Description Consider 10 Boolean variables x1, x2, x3, x4, x5, x6, x7, x8, x9, and x10. Consider all pairs and triplets of distinct variables amon…

Trouble Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5388    Accepted Submission(s): 1494 Problem Description Hassan is in trouble. His mathematics teacher has given him a very difficult pro…

About Grisha N. 题目链接: http://acm.hust.edu.cn/vjudge/contest/126546#problem/A Description Grisha N. told his two teammates that he was going to solve all given problems at the quarter-finals, even if all his teammates wouldn't show up at the competiti…

C - Will It Stop?Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87794#problem/C Description Byteasar was wandering around the library of the University of Warsaw and at one of its facades he noticed…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2111 题意:知道背包容量和物品单价.体积.问能买到的最大价值? 注意:单价指的是单位体积的价格 思路:先把单价由高到低排序,然后从单价高的商品开始买 代码: #include<iostream> #include<algorithm> using namespace std; struct item { int pi,mi; }I[]; bool cmp(item a,item b) {…