You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

public class Solution { public int coinChange(int[] coins, int amount) { ) ; ]; dp[] = ; ;i <= amount ;i++ ) { dp[i] = Integer.MAX_VALUE; for(int k :coins) { if(i>=k && dp[i-k] != Integer.MAX_VALUE) { dp[i] = Math.min(dp[i-k] + ,dp[i]); } }…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

给定不同面额的硬币 coins 和一个总金额 amount.编写一个函数来计算可以凑成总金额所需的最少的硬币个数.如果没有任何一种硬币组合能组成总金额,返回 -1. 示例 1: 输入: coins = [1, 2, 5], amount = 11 输出: 3 解释: 11 = 5 + 5 + 1 示例 2: 输入: coins = [2], amount = 3 输出: -1 说明: 你可以认为每种硬币的数量是无限的. 动态规划 class Solution { public: int coin…

""" You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination…

动态规划(DP)算法     动态规划是运筹学的一个分支,是求解决策过程最优化的数学方法.利用各个阶段之间的关系,逐个求解,最终求得全局最优解,需要确认原问题与子问题.动态规划状态.边界状态.边界状态结值.状态转移方程. 一.爬楼梯leetcode70: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how m…

参考https://blog.csdn.net/libosbo/article/details/80038549 动态规划是求解决策过程最优化的数学方法.利用各个阶段之间的关系,逐个求解,最终求得全局最优解,需要确认原问题与子问题.动态规划状态.边界状态.边界状态结值.状态转移方程. 以下每个例题,注意分析迭代关系是怎么找到的. 一.爬楼梯leetcode70: You are climbing a stair case. It takes n steps to reach to the top…