poj3255 Roadblocks

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POJ3255 Roadblocks [Dijkstra，次短路]

题目传送门 Roadblocks Description Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too quickly, because she likes the scenery along the way. She has decided to take…

Roadblocks Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13594 Accepted: 4783 Description Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too…

poj3255 Roadblocks 次短路

Roadblocks Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10098 Accepted: 3620 Description Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too…

POJ3255 Roadblocks 【次短路】

Roadblocks Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 7760 Accepted: 2848 Description Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too q…

POJ3255(Roadblocks)--次短路径

点这里看题目 3228K 485MS G++ 2453B 根据题意和测试用例知道这是一个求次短路径的题目.次短路径,就是比最短路径长那么一丢丢的路径,而题中又是要求从一点到指定点的次短路径,果断Dijkstra. R (1 ≤ R ≤ 100,000,N (1 ≤ N ≤ 5000) ,length D (1 ≤ D ≤ 5000),所以我用链式向前星方法存储,这个不知道的点这里(我转载别人的,讲的挺详细). 用一个二维数组dist[MAXN][2],去记录i->j的最短路径和次短路径,第二维是…

POJ3255 Roadblocks 严格次短路

题目大意:求图的严格次短路. 方法1: SPFA,同时求单源最短路径和单源次短路径.站在节点u上放松与其向量的v的次短路径时时,先尝试由u的最短路径放松,再尝试由u的次短路径放松(该两步并非非此即彼). 由u的最短路径放松: if(u->Dist + e->Weight < v->Dist) v->Dist2=v->Dist; //此处隐藏最短路放松.次短路不在此固定,Dist2可能在由u次短路放松时被放松得更短 if(u->Dist + e->Weight…

poj图论解题报告索引

最短路径: poj1125 - Stockbroker Grapevine(多源最短路径,floyd) poj1502 - MPI Maelstrom(单源最短路径,dijkstra,bellman-ford,spfa) poj1511 - Invitation Cards(单源来回最短路径,spfa邻接表) poj1797 - Heavy Transportation(最大边,最短路变形,dijkstra,spfa,bellman-ford) poj2240 - Arbitrage(汇率问题,…