Palindromic Matrix time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Let's call some square matrix with integer values in its cells palindromic if it doesn't change after the order of rows i…

任意门:http://codeforces.com/contest/1118/problem/C C. Palindromic Matrix time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Let's call some square matrix with integer values in its cells palind…

个人心得:其实本来这题是有规律的不过当时已经将整个模拟过程都构思出来了,就打算试试,将每个字符和总和用优先队列 装起来,然后枚举每个点,同时进行位置标志,此时需要多少个点的时候拿出最大的和出来,若不满足就输出No,结果一直卡在三组 数据.比赛完后一想,优先队列虽然用处大,不过当行列存在奇数的时候此时只要2个就可以,而如果你从最大的4个中拿出来, 那么下一层循环中必然有一个位置无法填充,如此就导致了算法的失败.所以后面建立个奇偶判定就好了. 感悟: 多注意思考和细节,从不同的层次看待问题,既可以全…

https://codeforces.com/contest/1118/problem/C 在查找元素的时候,必须按4,2,1的顺序进行.因为,如果先找1,可能就把原来的4拆散了,然后再找4,就找不到了 #include<bits/stdc++.h> using namespace std; ][]; int main(){ int n; cin>>n; map<int,int> mp; int t; ;i<n*n;i++){ cin>>t; mp[t…

题意 给出一个小写字母组成的字符矩阵,问能否通过重排其中的字符使得每行每列都是回文串. 分析 简化版:给出一个字符串,问能否通过重排其中的字符使得它是回文串.那么如果字符串长度为偶数,就需要a到z的个数都是2的倍数,如果长度是奇数,就需要恰好有一种字母的个数不是2的倍数. 那么拓展到二维的情况也差不多. 假设行数为n,列数为m. 1.n和m均为偶数: 最简单的情况,只需要所有字母的个数都是4的倍数 2.n为偶数,m为奇数:(n为奇数m为偶数的情况相同) 那么在刨掉一个长度为n的回文串之后所有字母…

彩笔看到题目后,除了懵逼,没有啥反应了,唯一想的就是 这是不是dp啊?看了题解才发现,原来是这样啊. 画几个矩阵看看就能看出来规律. 思路:先假设这是个M * N的矩阵 如果M和N都是偶数,则每个出现的字母的个数都必须是偶数个,如果有某个字母出现奇数个的话,肯定不会对称,因为M和N都是偶数,所以每个字母肯定出现次数是4的倍数.假设右上角是字母a,则另外三个角肯定也是a,所以至少4个,里面的字母也是这样. 如果M和N一个奇数,一个偶数,则字母出现的次数,是2的倍数或者4的倍数.假设矩阵高度为奇数,…

题意:给你\(n\)个数,判断是否能构成一个\(n\)X\(n\)的回文矩阵,若可以,输出\(YES\)和矩阵,否则输出\(NO\). 题解:如果这个矩阵的行/列元素是偶数的话,很好办,所有出现的数一定是\(4\)的倍数,我们直接判断然后模拟输出一下即可.如果是奇数,就要麻烦一点,我们首先用桶存一下所有元素的出现次数,然后直接模拟,首先奇数矩阵的左上右上左下右下一定是对称的,所以我们可以先看左上角的一个小块,模拟一下,每次可以确定\(4\)个位置.之后就是两行中心线了,除了中心,每个位置的元素的…

A. Water Buying 链接:http://codeforces.com/contest/1118/problem/A 实现代码: #include<bits/stdc++.h> using namespace std; #define ll long long int main() { ll n,a,b,m; cin>>n; ;i <= n;i ++){ cin>>m>>a>>b; <= b) cout<<m*a…

A - Snuke's favorite YAKINIKU -- #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ') #define enter putchar('\n') #define MAXN 40005 #define…

补一发A的题解. A - Snuke's favorite YAKINIKU 题意: 输入字符串S,如果以YAKI开头输出Yes,否则输出No. #include<bits/stdc++.h> using namespace std; int main() { char s[20];cin>>s; int n=strlen(s); if(n<4)puts("No"); else { if(s[0]=='Y'&&s[1]=='A'&&…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. (1) class Solution { public: string longestPalindrome(string s) { if (s ==…

题目: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 代码: class Solution { public: string longestPalindrome(string s) { const…

Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Example 2: Input: "cbbd"…

问题大意是在给定字符串中查找最长的回文子串,所谓的回文就是依据中间位置对称的字符串,比如abba,aba都是回文. 这个问题初一看,非常简单,但是会很快发现那些简单的思路都会带来O(n^3)级别的时间复杂度,n为传入字符串的实际长度.比如说下面的代码中的暴力枚举 for(i = 0; i < n; i = i + 1) for(j = i + 1; j < n; j = j + 1) ti = i, tj = j while(ti < tj && s[ti] == s[t…

今天我们要讲的是ng2的路由的第二部分,包括路由嵌套.路由生命周期等知识点. 例子 例子仍然是上节课的例子:…

题目描述 Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 即给定一个字符串,求它的最长回文子串的长度(或者最长回文子串). 解法一 对于一个问题,一定可以找到一个傻的可爱的暴力解法,本题的暴力解法即…

March 16, 2016 Problem statement:Given a 2D array (matrix) named M, print all items of M in a spiral order, clockwise.For example: M  =  1   2   3   4   5       6   7   8   9  10      11  12  13  14  15      16  17  18  19  20 The clockwise spiral pr…

Atitit Data Matrix dm码的原理与特点 Datamatrix原名Datacode,由美国国际资料公司(International Data Matrix, 简称ID Matrix)于1989年发明. Datamatrix是一种矩阵式二维条码,其发展的构想是希望在较小的条码标签上存入更多的资料量.Datamatrix的最小尺寸是目前所有条码中最小的,尤其特别适用于小零件的标识,以及直接印刷在实体上. Datamatrix又可分为ECC000-140与ECC200两种类型,ECC0…

转自:http://www.cnblogs.com/qiengo/archive/2012/06/30/2570874.html#translate Matrix的数学原理 在Android中,如果你用Matrix进行过图像处理,那么一定知道Matrix这个类.Android中的Matrix是一个3 x 3的矩阵,其内容如下: Matrix的对图像的处理可分为四类基本变换: Translate           平移变换 Rotate                旋转变换 Scale    …

题目来自 https://leetcode.com/problems/longest-palindromic-substring/ 题目:Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 给一个字符串…

Affine Transformation是一种二维坐标到二维坐标之间的线性变换,保持二维图形的"平直性"和"平行性".仿射变换可以通过一系列的原子变换的复合来实现,包括:平移(Translation).缩放(Scale).翻转(Flip).旋转(Rotation)和错切(Shear). 在做2D图形引擎时,仿射变换是非常重要的点,图形的旋转等各种表现都需要通过仿射变换来完成,比如在显示列表树中,父节点旋转了,那么子节点在计算显示时也要叠加上父节点的变换矩阵,这是叠…

Given a n x n matrix where each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix. Note that it is the kth smallest element in the sorted order, not the kth distinct element. Example: matrix = [ [ 1, 5…

Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ro…

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. click to show follow up. Follow up: Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple improvement uses O…

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] 此题跟之前那道Spiral Matrix 螺旋矩阵 本质上没什么区别,就相当于个类似逆运算的过…

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. For example,Given the following matrix: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] You should return [1,2,3,6,9,8,7,4,5]. 这道题让我们将一个矩阵按照螺旋顺序打印出来,我们…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 这道题让我们求最长回文子串,首先说下什么是回文串,就是正读反读都一样的字符串,比如 "bob", "level", &q…

Kaka's Matrix Travels Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9567   Accepted: 3888 Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka mo…