题目 Description: Count the number of prime numbers less than a non-negative number, n. Credits: Special thanks to @mithmatt for adding this problem and creating all test cases. Hint: Let's start with a isPrime function. To determine if a number is pri…

题目: Description: Count the number of prime numbers less than a non-negative number, n. 思路: 题意:求小于给定非负数n的质数个数 西元前250年,希腊数学家厄拉多塞(Eeatosthese)想到了一个非常美妙的质数筛法,减少了逐一检查每个数的的步骤,可以比较简单的从一大堆数字之中,筛选出质数来,这方法被称作厄拉多塞筛法(Sieve of Eeatosthese). 具体操作:先将 2~n 的各个数放入表中,然…

题目 The count-and-say sequence is the sequence of integers beginning as follows: 1, 11, 21, 1211, 111221, - 1 is read off as "one 1" or 11. 11 is read off as "two 1s" or 21. 21 is read off as "one 2, then one 1" or 1211. Given…

Leetcode(4)寻找两个有序数组的中位数 [题目表述]: 给定一个字符串 s,找到 s 中 最长 的回文子串.你可以假设 s 的最大长度为 1000.' 第一种方法:未完成:利用回文子串的特点 一开始我的思路如下:回文子串的特点是首尾字母相同,所以我对每一个字母都找到位于它后面的相同字母,利用切片判断这一段是否为回文子串(str[i:j]==str[i:j][::-1]).时间复杂度很高,主要是因为str.find操作非常耗时. class Solution(object): def lo…

题目 Follow up for H-Index: What if the citations array is sorted in ascending order? Could you optimize your algorithm? 分析 同LeetCode(274)H-Index第二个版本,给定引用数量序列为递增的:这就省略了我们的第一个排序步骤: O(n)的时间复杂度,遍历一次即可. AC代码 class Solution { public: int hIndex(vector<int>…

题目 Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k. 分析 题目描述:给定一个整数序列,查找是否存在两个下标分别为i和j的元…

题目 Follow up for "Find Minimum in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 migh…

题目 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times).…

题目 Given a binary tree struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; } Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL. Initially,…

题目 Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22, 分析 本题目与上一题LeetCode(112) Path Sum虽然类型相同,但是需要在以前的基础上,多做处理一些: 与Path Sum相比,本题是求出路径,所以,在找到满足的路…