LeetCode OJ--Reverse Nodes in k-Group **】的更多相关文章

Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
问题描述:1->2->3->4,假设k=2进行反转,得到2->1->4->3:k=3进行反转,得到3->2->1->4 算法思想:基本操作就是链表反转,将k个元素当作滑动窗口,依次进行反转. public class ReverseNodesInKGroup { public ListNode reverseKGroup(ListNode head, int k) { if (k == 1 || head == null || head.next ==…
Leetcode 25. Reverse Nodes in k-Group 以每组k个结点进行链表反转(链表) 题目描述 已知一个链表,每次对k个节点进行反转,最后返回反转后的链表 测试样例 Input: k = 2, 1->2->3->4->5 Output: 2->1->4->3->5 Input: k = 3, 1->2->3->4->5 Output: 3->2->1->4->5 详细分析 按照题目要求…
题目链接: https://leetcode.com/problems/reverse-nodes-in-k-group/?tab=Description   Problem :将一个有序list划分为k个组,并且每个组的元素逆置   链表操作 :递归算法  每次寻找到该组的尾部,然后进行逆置操作,返回头部,这样每次递归操作之后能够进行下一次的逆置操作. 链表操作画图比较形象!!!! 对于递归算法:找到共同点,找到程序退出点,注意特殊情况 本题中,共同点为每组为k个节点,并且每组进行的操作均为逆…
Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the valu…
题目 Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes…
题目描述:Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
这是LeetCode里的第25道题. 题目要求: 给出一个链表,每 k 个节点一组进行翻转,并返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度.如果节点总数不是 k 的整数倍,那么将最后剩余节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应当返回: 2->1->4->3->5 当 k = 3 时,应当返回: 3->2->1->4->5 说明 : 你的算法只能使用常数的额外空间…
前言   [LeetCode 题解]系列传送门:  http://www.cnblogs.com/double-win/category/573499.html   1.题目描述 Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out no…
原题: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
1 题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, on…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
题目描述: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, on…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
We are given a binary tree (with root node root), a target node, and an integer value `K`. Return a list of the values of all nodes that have a distance K from the target node.  The answer can be returned in any order. Example 1: Input: root = [3,5,1…
这题有点繁琐,在更新指针时很容易出错. ListNode *reverseKGroup(ListNode *head, int k) { )return head; ListNode dummy(-); dummy.next = head; for (ListNode *prev = &dummy, *end = head; end; end = prev->next) { ; i < k; i++) end = end->next; if (end == nullptr)bre…
We are given a binary tree (with root node root), a target node, and an integer value K. Return a list of the values of all nodes that have a distance K from the target node. The answer can be returned in any order. Example 1: Input: root = [3,5,1,6,…
居然把头插法写错了,debug了一个多小时 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseKGroup(ListNode* head, int k) { || head == nul…
题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
There are n cities connected by m flights. Each fight starts from city u and arrives at v with a price w. Now given all the cities and fights, together with starting city src and the destination dst, your task is to find the cheapest price from src t…
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ le…
题目:Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 25: Reverse Nodes in k-Grouphttps://oj.leetcode.com/problems/reverse-nodes-in-k-group/ Given a linked list, reverse the nodes of a linked list k at a time and return its modified list.If th…
题目描述 Leetcode 24 题主要考察的链表的反转,而 25 题是 24 的拓展版,加上对递归的考察. 对题目做一下概述: 提供一个链表,给定一个正整数 k, 每 k 个节点一组进行翻转,最后返回翻转后的新链表. k 的值小于或等于链表的长度,如果节点总数不是 k 的整数倍,将最后一组剩余的节点保持原有顺序. 注意: 算法只能使用常数的空间 不能单纯的改变节点内部的值,需要进行节点交换. 举例: Example: Given 1->2->3->4->5. For k = 2,…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…