BUY LOW, BUY LOWER Time Limit: 1000MS   Memory Limit: 30000K Total Submissions:11148   Accepted: 3920 Description The advice to "buy low" is half the formula to success in the bovine stock market.To be considered a great investor you must also f…
P2687 [USACO4.3]逢低吸纳Buy Low, Buy Lower 题目描述 “逢低吸纳”是炒股的一条成功秘诀.如果你想成为一个成功的投资者,就要遵守这条秘诀: "逢低吸纳,越低越买" 这句话的意思是:每次你购买股票时的股价一定要比你上次购买时的股价低.按照这个规则购买股票的次数越多越好,看看你最多能按这个规则买几次. 给定连续的N天中每天的股价.你可以在任何一天购买一次股票,但是购买时的股价一定要比你上次购买时的股价低.写一个程序,求出最多能买几次股票. 以下面这个表为例,…
BUY LOW, BUY LOWER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 9244 Accepted: 3226 Description The advice to "buy low" is half the formula to success in the bovine stock market.To be considered a great investor you must also follo…
第一眼看到题目,感觉水水的,不就是最长下降子序列嘛!然后写……就呵呵了..要判重,还要高精度……判重我是在计算中加入各种判断.这道题比看上去麻烦一点,但其实还好吧.. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #define rep(i,l,r) for(int i=l;i<r;i++) #define clr(x,c) memset(x,c,si…
题目描述 Description The advice to "buy low" is half the formula to success in the bovine stock market.To be considered a great investor you must also follow this problems' advice: "Buy low; buy lower" Each time you buy a stock, you must p…
Buy Low, Buy Lower 给出一个长度为N序列\(\{a_i\}\),询问最长的严格下降子序列,以及这样的序列的个数,\(1 <= N <= 5000\). 解 显然我们可以很轻易地求出严格下降子序列,思维的过程应该是从熟悉走向不熟悉,从自然走向不自然,因此还是照搬老套路,设\(f_i\)表示以i结尾的最长严格下降子序列的长度,\(g_i\)表示这样的序列的方案数. 接着我们发现,方案之所以不能照搬转移,关键在于结尾有多个相同的数,它们的方案发生了叠加,再仔细研究,你会发现,最靠近…
Buy Low, Buy Lower The advice to "buy low" is half the formula to success in the stock market. But to be considered a great investor you must also follow this problems' advice: "Buy low, buy lower" That is, each time you buy a stock, y…
Description The advice to "buy low" is half the formula to success in the bovine stock market.To be considered a great investor you must also follow this problems' advice: "Buy low; buy lower" Each time you buy a stock, you must purcha…
Description The advice to "buy low" is half the formula to success in the bovine stock market.To be considered a great investor you must also follow this problems' advice: "Buy low; buy lower" Each time you buy a stock, you must purcha…
如果没有方案数的话,这道题水的不得了,裸的最长下降子序列. 但是它有方案数,所以... 一个是方案数的求法: 设$f[i]$是以$a[i]$结尾的最长下降子序列的长度,可以$n^2$$dp$出答案 如果$a[j]>a[i],1<=j<=i-1$,可以更新$f[i]=max(f[i],f[j]+1)$,这个额老生常谈了 设$s[i]$是以$a[i]$结尾的最长下降子序列的方案数,在更新$f[i]$的时候可以顺便更新$s[i]$: 如果$f[i]==f[j]+1$,那么$s[i]=s[j]$…