题目: Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. 解析:同求全部组合的过程一样,只是这里限制每个组合中元素的个数为k,求所有组合时并不限制元素个数. 若要排除重复的元素,则首先对所有元素进行排序. 代码: public static List<List<Integer>> getAllCombinations(int[] array,int k)…
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 带回溯的递归.(带回溯没法用循环实现) class Solution { public List<List<Integer>&…
题目: Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] Hide Tags Backtracking 链接: http://leetcode.com/problems/combi…
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example, If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] class Solution(object): def combine(self, n, k): """ :ty…
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example, If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 做了好几个这种题了,就是 backtrack problem, 1小时做出,但不容易,各种小毛病. 我的程序蠢蠢的建立了一个 vec…
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Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. Example: Input: n = 4, k = 2 Output: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 题目…
