题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5104 rimes Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2844    Accepted Submission(s): 1277 Problem Description Given a number n, pleas…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5104 Primes Problem Description Given a number n, please count how many tuple$(p_1, p_2, p_3)$ satisfied that $p_1 \leq p_2  \leq p_3, $ $p_1,p_2,p_3$ are primes and $p_1 + p_2 + p_3 = n$. Input Multiple…

//宁用大量的二维不用量小的三维 #include <iostream> #include<cstdio> #include<cstring> using namespace std; ],num[]; int Cout; void initPrime() { ;i<=;i++) num[i]=; ;i<=;i++) { if(num[i]) { *i;j<=;j+=i) { num[j]=; } } } } int main() { initPrim…

Summation of primes Problem 10 The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. The code resemble : import math limit = 2000000 crosslimit = int(math.sqrt(limit)) #sieve = [False] * limit sieve =…

Primes Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2016    Accepted Submission(s): 928 Problem Description Given a number n, please count how many tuple(p1, p2, p3) satisfied that p…

Primes Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2841    Accepted Submission(s): 1276 Problem Description Given a number n, please count how many tuple(p1, p2, p3) satisfied that p…

Primes Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12    Accepted Submission(s): 11 Problem Description Given a number n, please count how many tuple(p1, p2, p3) satisfied that p1<=p…

The first two consecutive numbers to have two distinct prime factors are: 14 = 2  7 15 = 3  5 The first three consecutive numbers to have three distinct prime factors are: 644 = 2²  7  23 645 = 3  5  43 646 = 2  17  19. Find the first four consecutiv…

The number 3797 has an interesting property. Being prime itself, it is possible to continuously remove digits from left to right, and remain prime at each stage: 3797, 797, 97, and 7. Similarly we can work from right to left: 3797, 379, 37, and 3. Fi…

The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, are themselves prime. There are thirteen such primes below 100: 2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, and 97. How many circular primes are there…