HPU--1280 Divisible】的更多相关文章

最近在处理视频的时候,有这么一个需求 如果视频的分辨率宽度大于960的话,就把宽度设为960,而高度按其比例进行缩放 如果视频的分辨率高度大于540的话,就把高度设为540,而宽度按其比例进行缩放 之前用了很多方法都只能解决一部分 而且会报: "width / height not divisible by 2" 解决方法 如这种错误,就是说 宽度/高度不能被2除尽 其实解决方法也很简单,先看代码 //设置或保存ffmepg的参数 string ffmpegFormart = stri…
Very nice DP problem. The key fact of a mutual-divisible subset: if a new number n, is divisible with the largest number m within a mutual-divisible set s, s U {n} is also a mutal-divisible subset. class Solution { public: vector<int> largestDivisib…
17110 Divisible 时间限制:1000MS  内存限制:65535K 题型: 编程题   语言: 无限制 Description Given n + m integers, I1,I2,...,In,T1,T2,...,Tm, we want to know whether (I1*I2*...*In)%(T1*T2*...*Tm)= =0. 输入格式 The first line gives two integers n and m. 1<=n,m<=100 The second…
http://acm.hdu.edu.cn/showproblem.php?pid=1280 前m大的数 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10666 Accepted Submission(s): 3720 Problem Description 还记得Gardon给小希布置的那个作业么?(上次比赛的1005)其实小希已经找回了…
Highly divisible triangular number Problem 12 The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 21, 28, 36,…
A - Wilbur and Swimming Pool Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 596A Description After making bad dives into swimming pools, Wilbur wants to build a swimming pool in the sha…
这是杭电hdu上的链接http://acm.hdu.edu.cn/showproblem.php?pid=1280  Problem Description: 还记得Gardon给小希布置的那个作业么?(上次比赛的1005)其实小希已经找回了原来的那张数表,现在她想确认一下她的答案是否正确,但是整个的答案是很庞大的表,小希只想让你把答案中最大的M个数告诉她就可以了.  给定一个包含N(N<=3000)个正整数的序列,每个数不超过5000,对它们两两相加得到的N*(N-1)/2个和,求出其中前M大…
Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K. Example 1: Input: A = [4,5,0,-2,-3,1], K = 5 Output: 7 Explanation: There are 7 subarrays with a sum divisible by K = 5: [4, 5, 0, -2…
In a list of songs, the i-th song has a duration of time[i] seconds. Return the number of pairs of songs for which their total duration in seconds is divisible by 60.  Formally, we want the number of indices i < j with (time[i] + time[j]) % 60 == 0.…
Given a positive integer K, you need find the smallest positive integer N such that N is divisible by K, and N only contains the digit 1. Return the length of N.  If there is no such N, return -1. Example 1: Input: 1 Output: 1 Explanation: The smalle…